2 Questions on Ohm's Law and Power

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In a circuit with a single lamp of 3 ohms, adding identical lamps in series increases the total resistance to 6 ohms for two lamps and 9 ohms for three. When a 6-volt battery powers a lamp with 3 ohms of resistance, the current is 2 amps. The power dissipated in the circuit is 6 watts, calculated using the formula P = IV. The discussion emphasizes the importance of understanding how resistors behave when connected in series, specifically regarding total resistance and current flow. Clarification on the configuration of the lamps—whether in series or parallel—affects the overall resistance and current calculations.
Lovely
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If a single lamp has resistance of 3 ohms, and a second and third identical lamp is added wouldn't the second be 6, and third be 9.
If a part of an electric circuit diaaipates energy at 6 when it draws a current of 3A, what voltage is impressed across it? What does 6 represent
 
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How are the 2 lamps "added",in series,in parallel,mixed...?

As for the second,i think they mean 6W,thoough I'm not sure.

Daniel.
 
dextercioby said:
How are the 2 lamps "added",in series,in parallel,mixed...?

As for the second,i think they mean 6W,thoough I'm not sure.

Daniel.
Daniel,
The question is as followed: In a simple circuit 6-volt dry cell pushes charge through a single lamp whiich has a resistance of 3 ohms. the current through the circiut is 2 amps.
If a second identical lamp is connected in series, the 6 volt battery must push a charge through a total resistance of how many ohms. Same for third identical lamp
 
Well,what do you think...?What do you know about series coupled resistors...?What's the equivalent resistance...?

Daniel.
 
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