Relationship of Moments of Inertia

AI Thread Summary
The discussion centers on obtaining the polar moment of inertia (PMOI) using Unigraphics NX5.0, where users can access mass, volume, and moments of inertia about each axis. While the software does not directly provide the PMOI, it can be derived from the inertial tensor. The relationship between the conventional moments of inertia and the PMOI is expressed as J = I_x + I_y, with J representing the polar moment of inertia. Users are encouraged to utilize the radius of gyration to further understand the relationship between these values. Overall, the conversation emphasizes the need for understanding the mathematical relationships to compute the PMOI from available data.
minger
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Hey guys, I need some help. I have an old fortran program that needs axial moment of inertia as well as polar moment of inertia.

I have the part in Unigraphics NX5.0, where I can get the mass, volume, radius of gyration, and moment of inertias about each axis. However, I cannot find where to get polar moment of inertia.

So, I guess I either need someone who knows how to get J in NX, or some sort of relationship between the values I have and polar moment of inertia. I don't really think there is a direct relationship, but I'm struggling.

Thanks a lot guys,
 
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Every CAD program I have used will not give you the polar moment of inertia except for maybe solidworks, but they should all give you the inertial tensor which can be used to find the PMOI. There is a duality between conventional MOI and your PMOI. The PMOI is simply defined as:

J = \intr2dA

Of course wiki, has lots of info on it: http://en.wikipedia.org/wiki/Polar_moment_of_inertia

For relating the two to each other, look at radius of gyration: http://en.wikipedia.org/wiki/Radius_of_gyration
 
You can take that relationship one step further and say that

J = I_x + I_y

Attached is a quick example
 

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Oh fantastic. So, if I need the Mass and Polar Moment of Inertia about an axis, the normal MMOI is I_x (assuming x in the axial direction) and J = I_y + I_z.

Great, appreciate the help guys.
 
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