pitfall
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Dear users,
I wonder if there is anybody who can give me a hint on how to handle the following situation:
In the 2+1 dimensional Klein-Gordon equation with coordinates (t,x,y), I use as initial condition for \Psi(x,0) a spherically symmetric Gaussian. The relativistic dispersion relation is of course \omega^2=k_x^2+k_y^2.
I can now Fourier transform \Psi(x,0) to \Phi(k,0), no problem.
But when I want to calculate \Psi(x,t), by doing a second Fourier transformation, I get stuck because of the square root of the dispersion relation.
In other words, I can't solve the integral \int_{-\infty}^{+\infty} dk_x dk_y \exp\left( i k_x x+i k_y y - i \sqrt{k_x^2+k_y^2}t -\alpha^2(k_x^2+k_y^2)/2\right).
If anybody could give me a hint on this, I would be very thankful and happy, I already spent way too much time on this!
Thanks very much!
I wonder if there is anybody who can give me a hint on how to handle the following situation:
In the 2+1 dimensional Klein-Gordon equation with coordinates (t,x,y), I use as initial condition for \Psi(x,0) a spherically symmetric Gaussian. The relativistic dispersion relation is of course \omega^2=k_x^2+k_y^2.
I can now Fourier transform \Psi(x,0) to \Phi(k,0), no problem.
But when I want to calculate \Psi(x,t), by doing a second Fourier transformation, I get stuck because of the square root of the dispersion relation.
In other words, I can't solve the integral \int_{-\infty}^{+\infty} dk_x dk_y \exp\left( i k_x x+i k_y y - i \sqrt{k_x^2+k_y^2}t -\alpha^2(k_x^2+k_y^2)/2\right).
If anybody could give me a hint on this, I would be very thankful and happy, I already spent way too much time on this!
Thanks very much!