2nd Order Nonlinear ODE Question

frank1234
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Homework Statement



Solve the 2nd order nonlinear differential equation, with initial conditions y(0)=0 and y'(0)=1

y''=2ay^3-(a+1)y with a within [0,1]

It would be greatly appreciated if someone could point me in the right direction on this. Thanks!

Homework Equations


The Attempt at a Solution



I have rearranged the equation to be y''+ya+y=2ay^3
 
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frank1234 said:

Homework Statement



Solve the 2nd order nonlinear differential equation, with initial conditions y(0)=0 and y'(0)=1

y''=2ay^3-(a+1)y with a within [0,1]

It would be greatly appreciated if someone could point me in the right direction on this. Thanks!

Homework Equations





The Attempt at a Solution



I have rearranged the equation to be y''+ya+y=2ay^3

Not sure how much help it is to you, but assuming ##a>0## Maple gives a solution in terms of Jacobi functions:$$
y = \textrm{JacobiSN}(x,\sqrt a)$$
 
Hmmmm, I am not sure if that helps. I will have to give that some thought...
 
Any other suggestions on how to go about solving this would be helpful.
 
Use the identity y'' = y'\frac{dy'}{dy} = \frac12 \frac{d}{dy}(y'^2).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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