3 Phase Machine Line Current problem

AI Thread Summary
A user seeks assistance with calculating the line currents for a 415V, 50Hz, 3-phase load of 10kW at a power factor of 0.8 lagging. The correct line current is determined to be 17.39 Amps, using the formula I_LL = P_3φ / (V_LL√3PF). The discussion emphasizes the importance of correctly interpreting the power factor as cos(angle) rather than cos(PF). Clarifications are provided regarding the relationships between line-to-line voltage, phase voltage, and current in a star-connected system. Accurate calculations are crucial for resolving the current problem in three-phase systems.
AdamBG10
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Hi guys,

I would really appreciate some help with this problem(probably quite easy for anybody with Electrical Engineering experience).

Thanks in advance

Homework Statement



A 415V, 50Hz, 3-phase supply is connected to a 3 phase load of 10kw with a power factor of 0.8 lagging. Find the magnitude of the line currents.

Homework Equations



P = VICos(power factor)

Total Power = 3 V(p)I(p)cos(power factor)

The Attempt at a Solution



Attempted the question using the equations above, except I obtained the wrong answer.

Correct answer = 17.39Amps
 
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Assuming the 415V is line to line rms and that the 10kW is the total wattage for all three phases:

V_{\phi}=\frac{V_{LL}}{\sqrt{3}}
with V_{\phi} being a per phase voltage and V_{LL} being the line-to-line voltage.

Next, we know that:
P_{3\phi} = 3V_{\phi}I_{\phi}PF
with PF = powerfactor. And if this is star connected...
I_{\phi}=I_{LL}

so
P_{3\phi}=3\frac{V_{LL}}{\sqrt{3}}I_{LL}PF=\sqrt{3}V_{LL}I_{LL}PF
or
I_{LL}=\frac{P_{3\phi}}{V_{LL}\sqrt{3}PF}

You seem to be confusing something. cos(angle) = PF. You don't say cos(PF). As far as I know, cos(PF) means nothing of importance.
 
xcvxcvvc said:
Assuming the 415V is line to line rms and that the 10kW is the total wattage for all three phases:

V_{\phi}=\frac{V_{LL}}{\sqrt{3}}
with V_{\phi} being a per phase voltage and V_{LL} being the line-to-line voltage.

Next, we know that:
P_{3\phi} = 3V_{\phi}I_{\phi}PF
with PF = powerfactor. And if this is star connected...
I_{\phi}=I_{LL}

so
P_{3\phi}=3\frac{V_{LL}}{\sqrt{3}}I_{LL}PF=\sqrt{3}V_{LL}I_{LL}PF
or
I_{LL}=\frac{P_{3\phi}}{V_{LL}\sqrt{3}PF}

You seem to be confusing something. cos(angle) = PF. You don't say cos(PF). As far as I know, cos(PF) means nothing of importance.

Thanks very much!
 

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