- #1
kthouz
- 193
- 0
Let say that a+b=c
this can be writtem as
4a-3a+4b-3b=4c-3c
by arranging
4a+4b-4c=3a+3b-3c
taking out the constants
4*(a+b-c)=3*(a+b-c)
So 4=3
The mistake is that ... I'll post it soon. i read this from a notebook of my little brother and i firstly agreed to it but by the time i found out why not! Test your knowledge too.
this can be writtem as
4a-3a+4b-3b=4c-3c
by arranging
4a+4b-4c=3a+3b-3c
taking out the constants
4*(a+b-c)=3*(a+b-c)
So 4=3
The mistake is that ... I'll post it soon. i read this from a notebook of my little brother and i firstly agreed to it but by the time i found out why not! Test your knowledge too.