A 2.0-kg ball is travelling east at 8.0 ~ Momentum

  • Thread starter Thread starter Silverbolt
  • Start date Start date
  • Tags Tags
    Ball Momentum
AI Thread Summary
In a perfectly elastic collision involving a 2.0-kg ball traveling east at 8.0 m/s and a 3.0-kg ball traveling west at 10.0 m/s, both momentum and kinetic energy are conserved. The momentum principle states that the total initial momentum equals the total final momentum, leading to the equation M1Vi + M2Vi = M1Vf + M2Vf. Additionally, the conservation of kinetic energy can be expressed as 1/2(M1)(Vi)^2 + 1/2(M2)(Vi)^2 = 1/2(M1)(Vf)^2 + 1/2(M2)(Vf)^2. By applying these principles, the final velocities of both balls can be calculated. The solution involves solving these equations simultaneously to find the final velocities after the collision.
Silverbolt
Messages
24
Reaction score
0
A 2.0-kg ball is traveling east at 8.0 m/s when it has a perfectly elastic head-on collision with a 3.0-kg ball traveling west at 10.0 m/s. What are the final velocities of the two balls?

Please help I don't know where to start
 
Physics news on Phys.org
You know momentum is conserved when bodies collide, start with the momentum principle:
M1Vi + M2Vi = M1Vf + M2Vf

And try another formula, which represents the conservation of kinetic energy:

1/2(M1)(Vi)^2 + 1/2(M2)(Vi)^2 = 1/2(M1)(Vf)^2 + 1/2(M2)(Vf)^2
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Ambiguous question on momentum and how it works...
Replies
13
Views
1K
What are the final velocities of two balls after an elastic head-on collision?
Replies
5
Views
2K
Relative velocity passing a ball between two soccer players
Replies
5
Views
2K
Golf club 🏌️and ball ⛳ impulse problem
Replies
19
Views
2K
Conservation of momentum (wrecking ball hits a stationary object)
Replies
10
Views
3K
How to Calculate Speed of Head of Driver After Collision?
Replies
10
Views
2K
Solving the Elastric 3-Body Collision Problem
Replies
2
Views
2K
Question About Momentum: Ball Rolling up a Curved Ramp
Replies
12
Views
1K
Elastic collision of block on block
Replies
4
Views
2K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top