What is the acceleration and displacement of a ball rolling up and down a hill?

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The discussion revolves around calculating the acceleration and displacement of a ball rolling up and down a hill, starting with an initial velocity of 4.00 m/s and rolling down at 6.0 m/s after 5 seconds. Clarification is sought on whether the ball ascended for the entire 5 seconds before descending. It is suggested that the hill maintains a constant angle, allowing for a consistent gravitational acceleration component. The change in velocity over time provides the necessary data to determine the acceleration. Overall, the calculations hinge on understanding the motion dynamics influenced by gravity and the hill's incline.
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A ball rolls at an initial velocity of 4.00 m/s up a hill. 5 seconds later it is rolling down the hill at 6.0 m/s. <---- What does the question mean? Did the ball roll up for 5 seconds and then started rolling down?

Find its acceleration
Find its displacement at 5.0s
 
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Assume it didn't start at the bottom - so it mght be doing 6.0m/s below where it started
 
So did the ball go up 4.00 m/s for 5 secs or go up the hill for 20 meters and then started to roll down at 6 m/s?
 
the ball will be decelarating due to gravity then begins rolling downhill at increasing speed

I think you could assume the hill is at a constant angle so the component of gravity causing the acceleration is constant at g.cos(theta) for whatever theta is...

you know a time and a change in velocity so you should be able to get to what that acceleration is ...
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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