A capacitor Discharging into another capacitor

AI Thread Summary
When two capacitors charged in series are connected through a resistor, the charge will redistribute until both capacitors reach the same voltage. Initially, the charge on each capacitor is 133 micro coulombs, but the voltages across them differ due to their capacitances of 2 and 4 micro farads. Current flows from the capacitor with the higher voltage to the one with the lower voltage, similar to two voltage sources in series. This process continues until equilibrium is achieved, resulting in equal voltage across both capacitors. Ultimately, the charge will redistribute to balance the voltages while conserving total charge.
Jamessamuel
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I have charged two capacitors in series with a 100V cell such that now, there are electrons on the inside plate of one and the outside plate of the other, bunched up so that they incur a negative charge on each capacitor of 133micro coulombs.

Now, they are just connected to one another with a resistor to form a loop. how will the charge redistribute and why? I have been told that 133 micro coulombs would pass through the resistor but i see no reason as to why all the charge on the outer plate of one would just migrate entirely over to the other. The capacitances are 2 and 4 micro farads.

Regards
 
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After charging, charge on each capacitor will be same but voltages across both the capacitors will be different (which of course will add up to 100 V). So,when you connect them, its like two voltage sources in series. Current will flow from higher voltage capacitor to lower voltage capacitor until both are at the same voltage level. So,the charge will redistribute to bring them to equilibrium.
 
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