A container holds 8.0kg of water at 25degC....

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To determine the energy required to convert 8.0 kg of water at 25°C to 2.0 kg of steam, the relevant formulas for heating and phase change must be used. The total energy calculation involves both the specific heat capacity of water and the latent heat of vaporization. The formula applied is Q total = mcwΔt + msLf, where Q total represents the total energy, m is mass, c is specific heat, Δt is the temperature change, and Lf is the latent heat. The calculated energy amounts to approximately 7.12 million joules. Including all units in the calculations is essential for clarity and accuracy.
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Homework Statement


how much energy must be added to the water to create 2.0 kg of steam?

Homework Equations

The Attempt at a Solution


I have no idea how I am supposed to figure the answer out. what formulas do I use?
 
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What formula do you know that is related to heating and/or transforming material from one physical state to another? Those are the two processes which must occur here.
 
americanforest said:
What formula do you know that is related to heating and/or transforming material from one physical state to another? Those are the two processes which must occur here.
q=mLv
 
i attempted the answer:

Q total=mcwΔt+msLf
=8.0kg*4200j/kg*(100°C-25°C)+2.0kg*2.3*106
=7.12*106J
 
MaryBarnes said:
i attempted the answer:

Q total=mcwΔt+msLf
=8.0kg*4200j/kg*(100°C-25°C)+2.0kg*2.3*106
=7.12*106J
Yes.
If you want to make your working letter-perfect, include all units: 8.0kg*4200J/kg/°C*(100°C-25°C)+2.0kg*2.3*106J/kg.
 
haruspex said:
Yes.
If you want to make your working letter-perfect, include all units: 8.0kg*4200J/kg/°C*(100°C-25°C)+2.0kg*2.3*106J/kg.
awesome! thanks for the help!
 
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