A Critical Value for Transition in Differential Equations

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SUMMARY

The discussion centers on solving the initial value problem (IVP) for the differential equation ty' + 2y = (sin t)/t with the condition y(−π/2) = a. The general solution derived is y = ∏2a/4t² - cos(t)/t². The critical value a0 represents the transition point in the behavior of the solution as t approaches zero, which requires evaluating the limit of y(t) as t approaches zero in relation to a.

PREREQUISITES
  • Understanding of first-order differential equations
  • Familiarity with initial value problems (IVP)
  • Knowledge of limits and continuity in calculus
  • Experience with trigonometric functions and their properties
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  • Learn about the behavior of solutions near singular points
  • Explore the method of evaluating limits in differential equations
  • Investigate the implications of parameter changes on solution behavior
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Students and educators in mathematics, particularly those focusing on differential equations, as well as researchers analyzing transition behaviors in mathematical models.

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Homework Statement



Q) ty' + 2y = (sin t)/t, y(−π/2) = a, t < 0 . Let a0 be
the value of a for which the transition from one type of behavior to another occurs.Solve the IVP and find the critical value a0 exactly.

Homework Equations



DE

The Attempt at a Solution



I can easily manage to get the general solution. After a series of work, I ended with y= ∏2a/4t2 - cost/t2 . My biggest problem here is getting a0, the critical value. I mean what is exactly the critical value. In this case I cannot equate y' to be zero. I want a general explanation on what the critical value means!?
 
Last edited:
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Consider ##\lim\limits_{t\to 0}y(t)## in dependence on ##a##
 

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