- #1
Cc518
- 23
- 0
Homework Statement
The father stands at the summit of a conical
hill as he spins his 20 kg child around on a 5.0 kg cart with a
2.0-m-long rope. The sides of the hill are inclined at 20 degrees. He
keeps the rope parallel to the ground, and friction is negligible.
What rope tension will allow the cart to spin with the same
14 rpm it had in the example?
Homework Equations
F=mrw^2
The Attempt at a Solution
I drew the fbd diagram, and I got two equation :1. Fny +Ty=mg and 2. Tx-Fnx=mrw^2
where Fnx and Fny is the x, y-component of the normal force, Tx and Tx is the x, y-component of the Tension.
But I don't know how to solve for Fn
Can anyone help me?
The link to the image: https://cloud.smartdraw.com/share.aspx/?pubDocShare=3584F28114431EA1F27BA700C6061213131
Attachments
Last edited by a moderator: