A feather and a ball falling with air resistance

BSH
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Homework Statement


Suppose you drop a feather and a steel ball of equal masses (0.014 kg) at the same time from a height of 2.2 m and you are told that the feather hits the floor 3.5 s after the steel ball. Estimate the value of the terminal velocity of the feather in air. Then, estimate the feather's drag coefficient.

Homework Equations


mg - cv = ma

The Attempt at a Solution


I did the calculus as I've done many times before and got that v=(mg/c)(1-e^(-ct/m)) and the terminal veocity = mg/c. The only other thing I feel I could do is assume the air resistance experienced by the ball is negligible, but I don't know how that helps me if I know so little about the feather.
 
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Follow-up: do I have to use conservation of energy?
 
BSH said:

Homework Statement


Suppose you drop a feather and a steel ball of equal masses (0.014 kg) at the same time from a height of 2.2 m and you are told that the feather hits the floor 3.5 s after the steel ball. Estimate the value of the terminal velocity of the feather in air. Then, estimate the feather's drag coefficient.

Homework Equations


mg - cv = ma

The Attempt at a Solution


I did the calculus as I've done many times before and got that v=(mg/c)(1-e^(-ct/m)) and the terminal veocity = mg/c. The only other thing I feel I could do is assume the air resistance experienced by the ball is negligible, but I don't know how that helps me if I know so little about the feather.
I think that you should be able to calculate, or at least estimate c, to get a numerical answer for the terminal velocity of the feather. You know how long the steel ball is in the air (it's safe to assume no air resistance), and you know that the feather takes 3.5 sec. longer.

I haven't worked through this problem, but that's the tack I would take.
 
With air resistance there is no "conservation if energy".
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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