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cy19861126

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A 2.00-kg aluminum block and a 6.00-kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle 30.0) as shown in Figure P4.53. Making use of Table 4.2, determine (a) the acceleration of the two blocks and (b) the tension in the string.

My work so far:

For the aluminum block - I got T = 2a, which I cannot solve

For the copper block - I got Tx-58.8sin(30) = 6a - this is for x direction

and

Ny-58.8cos(30) = 6a - this is for y direction

58.8 is the weight force, which comes from 6*9.8 = 58.8N

T = tension force

N = Normal force

All the equations won't get me to solve for acceleration for either blocks

Thanks~~

If you cannot see the attachment, you may click http://students.washington.edu/cy1126/P4.53.jpg"

My work so far:

For the aluminum block - I got T = 2a, which I cannot solve

For the copper block - I got Tx-58.8sin(30) = 6a - this is for x direction

and

Ny-58.8cos(30) = 6a - this is for y direction

58.8 is the weight force, which comes from 6*9.8 = 58.8N

T = tension force

N = Normal force

All the equations won't get me to solve for acceleration for either blocks

Thanks~~

If you cannot see the attachment, you may click http://students.washington.edu/cy1126/P4.53.jpg"

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