- #1
Nikitin
- 735
- 27
[SOLVED] A hard differential equation - where is the error in my logic?
2xyy' + y2, where y is a function of x
2xyy' + y2 = 12x2 |*(1/x)
=> (y2)' + y2/x =12x |*ln(x), 2yy' = (y2)'
=> (y2ln(x))' = 12x*ln(x)
=> y2ln(x) = ∫12x*ln(x)
=> y2ln(x) = 6x2ln(x) -3x2 + C
=> y = ±sqrt[3x2(2-1/ln(x)) + c/ln(x)]
Well, my result is wrong. Can somebody tell me the error in my logic? HELP, my math exam is on the 4th of June...
Homework Statement
2xyy' + y2, where y is a function of x
The Attempt at a Solution
2xyy' + y2 = 12x2 |*(1/x)
=> (y2)' + y2/x =12x |*ln(x), 2yy' = (y2)'
=> (y2ln(x))' = 12x*ln(x)
=> y2ln(x) = ∫12x*ln(x)
=> y2ln(x) = 6x2ln(x) -3x2 + C
=> y = ±sqrt[3x2(2-1/ln(x)) + c/ln(x)]
Well, my result is wrong. Can somebody tell me the error in my logic? HELP, my math exam is on the 4th of June...
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