A jogger runs with a speed 3.25 m/s

Thread starter kinoa451
Start date Sep 29, 2009
Tags

Speed

AI Thread Summary

To find the X and Y components of the jogger's velocity, the jogger's speed of 3.25 m/s must be resolved into its components using trigonometric functions. The X component can be calculated using the cosine of the angle (30 degrees), while the Y component uses the sine of the angle. This results in the equations: Vx = 3.25 m/s * cos(30°) and Vy = 3.25 m/s * sin(30°). Understanding vector resolution is crucial for solving this problem effectively. The discussion emphasizes the importance of applying these concepts to break down the jogger's velocity into its respective components.

Sep 29, 2009

kinoa451

Homework Statement

A jogger runs with a speed of 3.25 m/s in a direction of 30(degrees) above the x axis.

Homework Equations

The Attempt at a Solution

Find the X and Y components of the jogger's velocity.

Physics news on Phys.org

Sep 29, 2009

kuruman

Science Advisor

Homework Helper

Education Advisor

Insights Author

Gold Member

Do you know how to resolve a vector into its components?

Sep 29, 2009

harvellt

Ever seen anything like \hat{x}+\hat{y}+\hat{z} or \hat{i}+\hat{j}+\hat{k}?

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Understanding Forces and their Vector Components'

I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?

View full post »