A lens and a convex mirror problem

[zimo]

Homework Statement

A body is positioned 40 cm from the left of a lens (f=30) and the lens is positioned 100cm left of a convex mirror (|R|=60), where will be the image and what type and magnitude will it have?

Homework Equations

1/u + 1/v = 1/f

The Attempt at a Solution

I tried to calculate the image after the lens - and got v = 120 cm.

Now, I don't know how to interpret the answer.
Can anyone help me out on this?

Thanks

 

[rl.bhat]

The convex mirror interrupt the rays to form the real image.
So (120 - 100) = 20 cm becomes the virtual object distance for the convex mirror. Now proceed.

 

[zimo]

That's my problem, now it is considered concave?

 

[ehild]

You can consider the mirror concave, and find the image distance that way, or you take it convex and use negative object distance.

ehild

 

[rwisz]

for your question. Based on the given information, the image will be located 120 cm to the right of the convex mirror, as you have correctly calculated. This means that the image will be virtual, as it is formed on the same side of the lens as the object. The type of image formed by a convex mirror is always virtual and upright.

As for the magnitude of the image, it can be calculated using the magnification equation:

m = -v/u

Where m is the magnification, v is the image distance, and u is the object distance. Plugging in the values, we get:

m = -(120 cm)/(40 cm) = -3

This means that the image will be 3 times smaller than the object.

Therefore, the final answer is:

The image will be located 120 cm to the right of the convex mirror, and it will be a virtual, upright image with a magnitude of -3.