A lens and a convex mirror problem

Click For Summary

Homework Help Overview

The problem involves a lens and a convex mirror setup, where a body is positioned at a specific distance from the lens, and the lens is located at a distance from the convex mirror. The original poster seeks to determine the image location, type, and magnitude based on the given parameters.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the image distance after the lens but expresses uncertainty about the interpretation of the result. Some participants discuss the implications of the image distance in relation to the convex mirror, questioning whether to treat the mirror as concave or convex.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the mirror's characteristics and how they affect the image formation. Guidance has been offered regarding the treatment of the mirror, but no consensus has been reached on the approach to take.

Contextual Notes

There is a lack of clarity regarding the nature of the mirror and how to apply the image distance calculated from the lens to the convex mirror setup. The original poster's calculations and assumptions are under scrutiny, and the discussion reflects differing views on the mirror's classification.

zimo
Messages
43
Reaction score
0

Homework Statement


A body is positioned 40 cm from the left of a lens (f=30) and the lens is positioned 100cm left of a convex mirror (|R|=60), where will be the image and what type and magnitude will it have?


Homework Equations


1/u + 1/v = 1/f


The Attempt at a Solution


I tried to calculate the image after the lens - and got v = 120 cm.

Now, I don't know how to interpret the answer.
Can anyone help me out on this?

Thanks
 

Attachments

  • problem_3_10.png
    problem_3_10.png
    1.6 KB · Views: 728
Physics news on Phys.org
The convex mirror interrupt the rays to form the real image.
So (120 - 100) = 20 cm becomes the virtual object distance for the convex mirror. Now proceed.
 
That's my problem, now it is considered concave?
 
You can consider the mirror concave, and find the image distance that way, or you take it convex and use negative object distance.

ehild
 
Last edited:

Similar threads

Replies
19
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
Replies
5
Views
3K