A long straight wire carries a (+) current of two amps in a direction

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The magnetic field generated by a long straight wire carrying a current can be calculated using the formula B = (μ₀I)/(2πr), where I is the current and r is the distance from the wire. In this case, the wire carries a current of 2 amps, and the distance from the wire is 0.5 meters. The angles mentioned in the discussion do not affect the calculation of the magnetic field strength. Therefore, the focus remains solely on the distance and current values provided. The resulting magnetic field strength can be determined using the specified formula.
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A long straight wire carries a (+) current of two amps in a direction 30 deg W of N. At apoint 0.5 m from the wire( in a direction 60 deg S of W) the magnetic field that it creates has size of how many Tesla.
 
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The magnetic field that an "inifite" current-carrying wire creates is:

B = \frac{\mu_0I}{2\pi r}

I being the current that it carries, r being the distance from the wire and \mu_0 = 4\pi * {10}^{-7}
 
As Chen pointed out, the answer depends only on the distance, which you are given. The angles given are irrelevant.
 
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