A Narrow Escape: Examining a Near-Miss in San Francisco

  • Thread starter Thread starter tnutty
  • Start date Start date
  • Tags Tags
    Escape
AI Thread Summary
The discussion revolves around a near-miss incident in San Francisco where a driver nearly hits a child while speeding. The driver receives a ticket for exceeding the speed limit of 25 mph, and calculations reveal that the car was actually traveling at approximately 36 mph at the time of the incident. The physics involved includes the coefficients of friction and the angle of the hill, which contribute to the car's stopping distance. Participants agree that the calculations indicate the driver was indeed speeding, suggesting that contesting the ticket would likely be futile. Ultimately, the consensus is that the driver should accept the ticket and prepare for potential increases in auto insurance rates.
tnutty
Messages
324
Reaction score
1

Homework Statement



While visiting a friend in San Francisco, you decide to drive around the city. You turn a corner and find yourself going up a steep hill. Suddenly a small boy runs out on the street chasing a ball. You slam on the brakes and skid to a stop, leaving a skid mark 50 ft long on the street. The boy calmly walks away, but a policeman watching from the sidewalk comes over and gives you a ticket for speeding. You are still shaking from the experience when he points out that the speed limit on this street is 25 mph.
After you recover your wits, you examine the situation more closely. You determine that the street makes an angle of 20° with the horizontal and that the coefficient of static friction between your tires and the street is 0.80. You also find that the coefficient of kinetic friction between your tires and the street is 0.60. Your car's information book tells you that the mass of your car is 1570 kg. You weigh 130 lb, and a witness tells you that the boy had a weight of about 60 lbs and took 3.0 s to cross the 15-ft wide street. Will you fight the ticket in court?

Homework Equations





The Attempt at a Solution



i got x: Ffriction + Fx

=

0.6mgCos(theta)+mosin(theta)
 
Physics news on Phys.org
Doing exam questions are a little dubious on the homework forum.

Besides you've shown no real effort.
 
Alright this an old exam question. Here is my progress :

use the equation v^2-v0^2 = 2x(x-x0)

by trig I figured out,

Fnet = F of friction + F of x direction

= 0.6mgCos(@)+mgSin(@)

so,

v^2 = 0, Vo^2 = ? ,

a = Fnet/m
=

g(0.6Cos(theta) +gsin(theta)).

so

Vo^2 = 2F/m(X-Xo)

= sqrt ( 2 (g(.6Cos(@) + sin(@))(15.14)

= 16.44m/s
 
So what does that translate to in mph?

Should you fight the ticket then?
 
that translates to 36mph. I am not sure if my logic is correct though, which
is why i wanted someone to check it.

IF this is correct then he is guilty.
 
tnutty said:
that translates to 36mph. I am not sure if my logic is correct though, which
is why i wanted someone to check it.

IF this is correct then he is guilty.

Yep. He should just mail in the fine and wait for his auto insurance rates to go up.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top