A pendulum on some moon has a length of 1.5meters and a period of

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A pendulum on a moon has a length of 1.5 meters and a period of 4.2 seconds, resulting in a calculated gravitational acceleration of approximately 3.36 m/s². The discussion shifts to determining how high a rock thrown 13 meters into the air on Earth would ascend if thrown with the same initial velocity on that moon. To find the initial velocity of the rock on Earth, the SUVAT equations are referenced, particularly focusing on the variables of displacement, initial velocity, final velocity, and acceleration. The relevant equation for this scenario is identified, though the specific equation is not stated. The conversation emphasizes the need to apply these physics concepts to solve the problem effectively.
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A pendulum on some moon has a length of 1.5meters and a period of 4.2seconds. On Earth a girl throws a rock 13meters in the air, if she was on that moon how high would that same rock go if she threw it with the same effect? (Ignore all air resistance)
 
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T=2\pi\sqrt{\frac{L}{g}}

g=\frac{4\pi^{2}L}{T^{2}}

g=\frac{4\pi^{2}1.5}{4.2^{2}}

g= 3.3570083m/s2

Does that help you a bit?
 


I found the gravity okay, it was the next part that I got hung up on.
 


Can you work out the initial velocity for the rock on the earth?
 


That's the train of thought that I had, but I don't know how I would do that.
 


Think of the SUVAT equations, you know,

S = 13m
U = ?
V = 0 as at the maximum height the velocity will be zero
A = g for Earth


T doesn't matter

Which SUVAT equation has those 4 variables in it - SUVA ?
 
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