Dehydration Problem: Solving for the Location of a Double Bond in a Carbocation

AI Thread Summary
The discussion revolves around solving a homework problem related to the formation of a double bond in a carbocation. The participant is confused about the location of the double bond, as it appears to be equally viable at two positions, labeled a and b. The suggestion to refer to Zaitsev's rule is made, highlighting the importance of substitution in determining the stability of the carbocation. Clarification is provided that the double bond does not form between the bridgehead carbons due to the specific reaction mechanism involved. The final advice encourages drawing the molecule in its enol form to facilitate further understanding of the reaction.
vijayramakrishnan
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Homework Statement


Please see question number 31

http://cms.fiitjee.co/Resources/DownloadCentre/Document_Pdf_183.pdf

Homework Equations


none

The Attempt at a Solution



i got up to second step in the solution(scroll downwards) but in the last step a carbocation is formed and double bond can be formed in two places b and a. they seem to be equivalent places,i don't know where the double bond will be formed.
 
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Look up Zaitsev's rule.
 
TeethWhitener said:
Look up Zaitsev's rule.
but here both are equally substituted sir
 
Ah, I see now. You're wondering why the double bond doesn't form between the two bridgehead carbons? This might be because you're envisioning protonating the OH group at the bridgehead carbon and eliminating a water to give a tertiary carbocation. In this case however, you have to do something a little different. Start by drawing the molecule in the enol form. Can you get it from here?
 
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