A problem regarding the lens formula

  • Thread starter Thread starter jxocq
  • Start date Start date
  • Tags Tags
    Formula Lens
AI Thread Summary
The discussion revolves around solving a problem involving a convex lens and the lens formula. The user expresses confusion about the correct application of the lens equation, particularly regarding the signs of the variables involved. Participants emphasize the importance of understanding the lens formula, which is 1/f = 1/v - 1/u, and suggest using ray diagrams for clarity. The user mentions being homeschooled and having difficulty grasping the concepts independently, leading to a reliance on the forum for assistance. Overall, the conversation highlights the challenges of learning optics and the need for clear visual aids in understanding lens behavior.
jxocq
Messages
6
Reaction score
1

Homework Statement


An arrow of 2cm length stands about 6cm away from a convex lens (f = 2cm). How long is the image of the arrow?

Homework Equations


-

The Attempt at a Solution


Whenever I get homework regarding optics and particularly the lens formula, I never really know where to start. I tried filling the numbers I've been given into the formula but I'm really unsure if I'm doing the right thing and if all the numb are entered in the correct places.
 
Physics news on Phys.org
First, write down the lens equation here, and tell us if you know what the symbols mean.

Zz.
 
ZapperZ said:
First, write down the lens equation here, and tell us if you know what the symbols mean.

Zz.

1/V - 1/U = 1/F is the formula right?
Where V is the distance of the image from the centre of the lens, U is the distance of the object of the centre of the lens and F is the focal length of the lens.
 
jxocq said:
1/V - 1/U = 1/F is the formula right?
Where V is the distance of the image from the centre of the lens, U is the distance of the object of the centre of the lens and F is the focal length of the lens.

Are you sure about the minus sign?

Zz.
 
ZapperZ said:
Are you sure about the minus sign?

Zz.
Yikes. I went to look on the internet now and different sources say multiple things. Maybe because it's a convex lens it should be 1/F = 1/V + 1/U ?
 
jxocq said:
Yikes. I went to look on the internet now and different sources say multiple things. Maybe because it's a convex lens it should be 1/F = 1/V + 1/U ?

Where did you get the minus sign in the first place? It has nothing to do with whether it is convex or concave.

Next, draw a picture and show in the sketch the distance representing V and U.

Zz.
 
ZapperZ said:
Where did you get the minus sign in the first place? It has nothing to do with whether it is convex or concave.

Next, draw a picture and show in the sketch the distance representing V and U.

Zz.
I'm not sure but something like this?
 

Attachments

  • IMG_0746.JPG
    IMG_0746.JPG
    19.9 KB · Views: 271
jxocq said:

Homework Statement


An arrow of 2cm length stands about 6cm away from a convex lens (f = 2cm). How long is the image of the arrow?

Homework Equations


-

The Attempt at a Solution


Whenever I get homework regarding optics and particularly the lens formula, I never really know where to start. I tried filling the numbers I've been given into the formula but I'm really unsure if I'm doing the right thing and if all the numb are entered in the correct places.
Note that for a convex lens, f is taken negative, so in the formula you should use f=-2 cm
 
  • #10
When drawing ray diagram, use as much space as you can... and use a straightedge.
The horizontal scale and vertical scale can be different.
What will also be important is to draw the lens plane and the lens' focal points.
 
  • #11
robphy said:
Learn to draw ray diagrams.
http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/raydiag.html
https://www.geogebra.org/m/KYNsUZXH
Due to various sign conventions, I find it difficult to just rely on formulas.
But with a ray diagram... i can see the physics better.
Then use that diagram to clarify the definitions in your formulas.
They do look kinda daunting but I'll be sure to learn to get better with them. I did a few assignments with them but i never really understand what I'm doing when I have to use them
 
  • #12
jxocq said:
I'm not sure but something like this?

You don't appear to understand what you either read, or wrote. You earlier wrote:

V is the distance of the image from the centre of the lens

Does this match your sketch?

What is puzzling me here is that it is as if you either don't have a textbook, or you never took any class notes. Why is this the case?

Even if that were the case, if you had done a search on "lens equation", you would have seen, for example, the hyperphysics site. This page clearly indicates what the lens equation means, and how to use it. So I am not sure why you are having a problem with this. I'm trying to figure out the source of the problem here.

Zz.
 
  • #13
ZapperZ said:
You don't appear to understand what you either read, or wrote. You earlier wrote:
Does this match your sketch?

What is puzzling me here is that it is as if you either don't have a textbook, or you never took any class notes. Why is this the case?

Even if that were the case, if you had done a search on "lens equation", you would have seen, for example, the hyperphysics site. This page clearly indicates what the lens equation means, and how to use it. So I am not sure why you are having a problem with this. I'm trying to figure out the source of the problem here.

Zz.
I'm homeschooled (It's a Dutch online school) so I do have a textbook and do make my homework, but I basically have to figure everything out by myself. I've mailed my teacher for explanation but their Christmas break has already started so I resorted to here. I just can't wrap my head around the lens formula
 
  • #14
In the thin lens formula ##\frac {1}{f}=\frac {1}{v}-\frac {1}{u}##, as you've already mentioned, ##u## & ##v## are distances of obj. & img. resp. from the center of the lens. Check that in your diagram you've marked the height of the arrow as ##v##.
 

Similar threads

Back
Top