A projectile problem (Olympiad)

AI Thread Summary
A rock launched vertically covers half of its total distance during the last second of its flight, leading to a question about the maximum duration of the flight. The discussion emphasizes ignoring air resistance to simplify the problem, as it is a standard uniform-acceleration scenario. Participants note that the rock does not necessarily have to return to the ground, which complicates the interpretation of its flight duration. The initial assumption of a 2-second flight is incorrect, prompting further exploration of the problem. The conversation highlights the importance of clarifying conditions in projectile motion problems.
Michael Si
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A rock is launched vertically. During the last second of the flight, the rock covers one-half of the entire distance covered during the flight. What is the maximum possible duration of the flight? (Hint: answer is not 2 seconds.)

I've tried to use integration to solve an equation of motion which includes air resistance but failed. Anyone can help me?
 
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Michael Si said:
A rock is launched vertically. During the last second of the flight, the rock covers one-half of the entire distance covered during the flight. What is the maximum possible duration of the flight? (Hint: answer is not 2 seconds.)

I've tried to use integration to solve an equation of motion which includes air resistance but failed. Anyone can help me?

Hi Michael! Welcome to PF! :smile:

i] ignore air resistance (this is a standard uniform-acceleration problem)

ii] you have noticed the question doesn't say the rock returns? :wink:

ii] show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:
 
Thank you. :smile: Well, you're right. Since the conditions aren't clearly stated, factors like air-resistance can be ignored so as to simplify the problem. And indeed, the rock would not necessarily return. But I am not sure where the rock would be if i doesn't fall back. :rolleyes:

If it follows a simple projectile trajectory (in which it falls back to the ground) without resistance and assuming constant acceleration, the answer would be 2 seconds, which isn't the desired answer. Then I considered air drag and formed and solved the differential equation m*dv/dt=mg-Dv^2, which gave me very complicated results. I knew it wasn't the right way then.

If the rock doesn't fall back, where would it go?
 
Michael Si said:
If the rock doesn't fall back, where would it go?

Well … either up or down!

"flight" doesn't include landing … :smile:
 
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