A question about electrostatics / Gauss's law

AI Thread Summary
The discussion revolves around a problem involving a conducting spherical shell with a charge of 3.00 nC and a central charge of -2 nC. The electric field calculations at various distances from the center reveal that the field is zero at r = 2.2 m due to the properties of conductors. The charge distribution indicates that the inner surface of the shell has +2 nC, while the outer surface has the remaining 1 nC. Participants clarify that the net charge within a Gaussian surface inside the conductor must equal zero, leading to the conclusion about charge allocation. Overall, the application of Gauss's law effectively explains the electric field behavior and charge distribution in this scenario.
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Homework Statement



Suppose a conducting spherical shell carries a charge of 3.00 nC and that a charge of -2 nC is at the center of the sphere. If the distance from the center to the inner shell is 2.00 m, and the distance from the center to the outer shell is 2.40 m, find the electric field at:

a.) r = 1.5 m from center
b.) r = 2.2 m from center
c.) r = 2.5 m from center
d.) What is the charge distribution on the sphere?

Homework Equations



Using Gauss's law and the principle of electric flux, I was able to correctly derive the equation:

(E)(r^2) = (Qinside)(ke)

E=electric field
ke = 9 x 10^9



The Attempt at a Solution



I was able to get parts (a) and (c) just be using the equation and plugging in the charges that I knew.

The answer for (b) = 0
the answer for (d) = 2.00 nC on the inner surface, 1.00 nC on the outer surface.


I have worked for like 2 days on this problem and couldn't figure it out. Please help! Thanks in advance.
 
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Well the answer for b) is 0. It is a conductor and charge within a conductor will lay at the surface.

http://hyperphysics.phy-astr.gsu.edu/Hbase/electric/gausur.html#c2

In d) since the field is 0, and the Gaussian surface within the conductor yields 0, then doesn't that mean that the net charge within is 0? If the center has -2nC, then won't the inner surface of the conductor necessarily have +2nC? and if 2 of them are on the inner surface ... what must be left of the 3nC that it is charged with to be lounging about on the outer surface?
 
LowlyPion said:
Well the answer for b) is 0. It is a conductor and charge within a conductor will lay at the surface.

http://hyperphysics.phy-astr.gsu.edu/Hbase/electric/gausur.html#c2

In d) since the field is 0, and the Gaussian surface within the conductor yields 0, then doesn't that mean that the net charge within is 0? If the center has -2nC, then won't the inner surface of the conductor necessarily have +2nC? and if 2 of them are on the inner surface ... what must be left of the 3nC that it is charged with to be lounging about on the outer surface?

I see. But why would 2 of them be on the inner surface?
 
physics213 said:
I see. But why would 2 of them be on the inner surface?

What's at the center?

-2nC.

What will the closed Gaussian surface within the middle of the conductor be? 0.

If the net of the charge inside the Gaussian must be 0, then 2nC must reside on the inner surface.
 
LowlyPion said:
What's at the center?

-2nC.

What will the closed Gaussian surface within the middle of the conductor be? 0.

If the net of the charge inside the Gaussian must be 0, then 2nC must reside on the inner surface.

ah ok. thanks a lot!
 
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