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A question about sepcial relativity

  • Thread starter wowolala
  • Start date
An astronaut traveling on the Helios satellite (the fastest human made craft) goes on a trip to Jupiter and back in 75 days as measured by an observer on the Earth. If the average speed of the satellite is a quarter of a million km/h with respect to the Earth , what is the time difference ( in seconds) between the time recorded by the clock on the Earth and the one on board the satellite?

honestly, i am realy confused on this part , can somebody help me?

thx so much

Answers and Replies

Science Advisor
Homework Helper
Hi wowolala! :smile:

Find the speed, v (as a multiple of c).

Then the clock on the satellite will go slow by … ?

Then multiply by the time (75 days converted into seconds). :smile: