A question about star's luminosity, temperature and mass.

In summary: H-R diagram suggests common denominators - such as mass and elemental composition. Low mass, high luminosity stars and high mass, low luminoisty stars are uncommon.Makes sense; I shall investigate further.
  • #1
pixel01
688
1
My question is : if two stars have the same luminosity and temperature, do they have to be at the same mass and size?
 
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  • #2
Typically yes - stars are pretty much blackbodies so their luminosity is a function of temperature and size.

edit - Although that would only be absolutely true for luminosity in the same band - in theory it would be possible for a small hot star to put out the same total energy as a large cool star.
 
  • #3
Except for metallicity effects, which can cause stars of the same luminosity and temperature to have drastically different masses.

Which was something I only realized, to my great consternation, about half-way through writing this one paper.
 
  • #4
If memory serves me correctly then. Luminosity = 4*pi*r^2*(boltzman constant)*T^4

(where t is temperature and r is the radius of the star).
 
  • #5
Whoa! I think it's far too rash to make these sweeping generalizations. The previous posters #2 #3 statements "absolutely true" or "true except for metallicity" are reckless. Stars with the same luminosity could have different sizes and masses for a lot of reasons. I think the age, composition, and the radiative or convective description of the star are paramount. I don't think luminosity is any simple function of a star's mass and size. I'll await an astrophysicist's verdicit on this one.
 
  • #6
Helios said:
Whoa! I think it's far too rash to make these sweeping generalizations. The previous posters #2 #3 statements "absolutely true" or "true except for metallicity" are reckless. Stars with the same luminosity could have different sizes and masses for a lot of reasons. I think the age, composition, and the radiative or convective description of the star are paramount. I don't think luminosity is any simple function of a star's mass and size. I'll await an astrophysicist's verdicit on this one.

I have just consulted the Hertzsprung-Russell diagram . It can be an answer for this quest.
 
  • #7
Apologies for the late arrival, but now I am in a position of having to ask similar questions to this; I have the task of offering up 'plausible' (if not necessary hyper-accurate) stellar statistics based on only a few initial conditions: mass (and perhaps constituency of that mass in H, He, and metallicities) versus age (how long it has been around.)

This nags me like knowing I know a word that is just beyond the tip of my tongue. I could use all these solar ratio based equations we have derived to 'guess' at a star's features, but it seems to me as though if you know initial mass you know everything. Initial gravity -> initial inward pressure -> required force to initiate fusion -> outward pressure from the energy released by said fusion -> hydrostatic equilibrium -> radius; meanwhile backtracking a bit, that released energy -> radius/surface area -> outward luminosity -> surface temperature. Oversimplistic perhaps, but is there anything missing here?
 
  • #8
~jet said:
Apologies for the late arrival, but now I am in a position of having to ask similar questions to this; I have the task of offering up 'plausible' (if not necessary hyper-accurate) stellar statistics based on only a few initial conditions: mass (and perhaps constituency of that mass in H, He, and metallicities) versus age (how long it has been around.)

This nags me like knowing I know a word that is just beyond the tip of my tongue. I could use all these solar ratio based equations we have derived to 'guess' at a star's features, but it seems to me as though if you know initial mass you know everything. Initial gravity -> initial inward pressure -> required force to initiate fusion -> outward pressure from the energy released by said fusion -> hydrostatic equilibrium -> radius; meanwhile backtracking a bit, that released energy -> radius/surface area -> outward luminosity -> surface temperature. Oversimplistic perhaps, but is there anything missing here?

Opacity. Heavier elements in the core means it has to be hotter to fuse and thus fusion goes quicker. That's why stars get brighter as they age on the Main Sequence. Luminosity is usually a simple function of effective temperature and stellar photospheric area - but increased opacity in very cool stars changes that simple relation.
 
  • #9
The fact stars can be binned in the H-R diagram suggests common denominators - such as mass and elemental composition. Low mass, high luminosity stars and high mass, low luminoisty stars are uncommon.
 
  • #10
qraal said:
Opacity. Heavier elements in the core means it has to be hotter to fuse and thus fusion goes quicker. That's why stars get brighter as they age on the Main Sequence. Luminosity is usually a simple function of effective temperature and stellar photospheric area - but increased opacity in very cool stars changes that simple relation.

Makes sense; I shall investigate further. May have more questions after the fact =)
 
  • #11
Chronos said:
The fact stars can be binned in the H-R diagram suggests common denominators - such as mass and elemental composition. Low mass, high luminosity stars and high mass, low luminoisty stars are uncommon.

Oh, I believe it; that's why I was surprised not to find a 'stellar' equation that could simply equate reasonably predictable stellar 'characteristics' based purely on initial mass and current age (the two details I will know at the outset of my programming.)
 
  • #12
Aside from opacity, would steadily decreasing mass (through dissemination of solar wind, energy, CMEs, etc) also technically increase a star's mass as it ages during its main sequence? Less gravity = less inward pressure = new hydrostatic equilibrium upwards = wider radius = more surface area to produce radiance = more luminosity. I realize that the difference might be slim, but can it be a factor? I've ready the sun is 20% brighter today than during its infancy.
 
  • #13
Whoa!

If two stars have the same temperature and luminosity, they *must* have the same size. That's a consequence of stars being blackbodies, and has nothing to do with any energy generating mechanism.

They do not have to have the exact same mass, although as a practical matter, it will be fairly close.
 
  • #14
Sure, but that's observing only the consequences of the mechanics going on rather than addressing them directly. If not for the energy inside producing resistance to a mass's overall gravity, you couldn't have a hydrostatic equilibrium determining said mass's radius at any given point in time.
 
  • #15
i think it's not always there, same luminosity and temperature does not make em of same size there are many stars in the universe which nearly as hot and as bright as the sun (the super red giants) but they are a way big than sun . and also there are starts who are as bright and luminous as proxima centauri but they are big in size . but if you mentioned the age factor also then it can be thought of
 
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  • #16
Rishavutkarsh, I am sorry, but none of that is true. The luminosity of a star is determined by its radius and temperature.
 
  • #17
Vanadium 50 said:
Rishavutkarsh, I am sorry, but none of that is true. The luminosity of a star is determined by its radius and temperature.

betelguese is brighter than sun ? sure it isn't it's just as luminous as proxima centauri but if the stages of life of two stars are also included then things can be said this way right?
 
  • #18
Rishavutkarsh said:
betelguese is brighter than sun ?

Yes. Technically, it's more luminous. The sun is brighter, but that's because it is closer.
 
  • #19
Vanadium 50 said:
Rishavutkarsh, I am sorry, but none of that is true. The luminosity of a star is determined by its radius and temperature.

And the opacity. In brown dwarfs the formation of dust and clouds obscures the purer black body output of very hot stars. In white dwarfs the thermal resistance of the crust means the star can have an average internal temperature much, much higher than its photosphere. Effective temperature is the equivalent purely blackbody temperature for a given luminosity and photospheric area and is usually pretty close to the spectral temperature. But deviations are what make astronomy interesting/challenging.
 
  • #20
Vanadium 50 said:
Yes. Technically, it's more luminous. The sun is brighter, but that's because it is closer.

Sure; BG is more luminous but due to its bloated dimensions, that is spread out so much more dramatically than either the sun or proxima centauri... you average down (for lack of a better term) to a lower, redder, cooler temperature despite the greater output.

I am curious... I've ready that at outset, a star born here in this galaxy and at this time is going to have X percent hydrogen and Y percent helium and trace amounts of heavier castoffs. When all that aggregates to the point of fusion, (assuming a modest sized star) we speak of it as if it is only fusion hydrogen. Is that technically true? Is there no helium being fused at all until it reaches the end of the main sequence? My mind wants to default to believing that this is occurring in a gradient of a sort, rather than sudden flips of a switch where internal shells of alternately fusing substances materialize.
 
  • #21
~jet said:
Sure; BG is more luminous but due to its bloated dimensions, that is spread out so much more dramatically than either the sun or proxima centauri... you average down (for lack of a better term) to a lower, redder, cooler temperature despite the greater output.

I am curious... I've ready that at outset, a star born here in this galaxy and at this time is going to have X percent hydrogen and Y percent helium and trace amounts of heavier castoffs. When all that aggregates to the point of fusion, (assuming a modest sized star) we speak of it as if it is only fusion hydrogen. Is that technically true? Is there no helium being fused at all until it reaches the end of the main sequence? My mind wants to default to believing that this is occurring in a gradient of a sort, rather than sudden flips of a switch where internal shells of alternately fusing substances materialize.

Each "step" has radically higher temperatures and densities at which its probability of occurring rises sufficiently to actually occur, plus each successive set of reactions involves heavier elements that can sink deeper - the heavier fusion "ash" of one reaction becomes the fuel of the next layer downwards because of that.
 
  • #22
qraal said:
Each "step" has radically higher temperatures and densities at which its probability of occurring rises sufficiently to actually occur, plus each successive set of reactions involves heavier elements that can sink deeper - the heavier fusion "ash" of one reaction becomes the fuel of the next layer downwards because of that.

Of course; I'm familiar with the concept of shells of fusing different elements... what I wasn't as certain about is what is there that prevents a little helium from being fused along the way prior to the formation of the first helium core? I have some difficulty perceiving the mechanisms by which, SNAP, all of a sudden a helium core spontaneously exists.

So the heavier material sinks; that makes sense... it accumulates... does it reach, maybe, some critical mass where it begins to fuse? It just seems to me that at the center of a star, given higher temps and pressures, some of it would be fusing prior to the formation of a shell.

We should all go dissect a star. =) I don't think the natives will mind.
 
  • #23
Of course; I'm familiar with the concept of shells of fusing different elements... what I wasn't as certain about is what is there that prevents a little helium from being fused along the way prior to the formation of the first helium core? I have some difficulty perceiving the mechanisms by which, SNAP, all of a sudden a helium core spontaneously exists.

Hello Jet, I've been reading along and I think I have a few answers. First, helium most certainly burns in the sun; however, the core is not hot enough to support large amounts of this cycle. I believe the p-p chain is responsible for 98% of the suns energy while the CNO is second with ~1.5%. Here is my source: http://neutrino.aquaphoenix.com/un-esa/sun/sun-chapter4.html
 
  • #24
CoolYoungStar said:
Hello Jet, I've been reading along and I think I have a few answers. First, helium most certainly burns in the sun; however, the core is not hot enough to support large amounts of this cycle. I believe the p-p chain is responsible for 98% of the suns energy while the CNO is second with ~1.5%. Here is my source: http://neutrino.aquaphoenix.com/un-esa/sun/sun-chapter4.html

Hah! Much appreciated! I shall investigate.
 
  • #25
CoolYoungStar said:
Hello Jet, I've been reading along and I think I have a few answers. First, helium most certainly burns in the sun; however, the core is not hot enough to support large amounts of this cycle. I believe the p-p chain is responsible for 98% of the suns energy while the CNO is second with ~1.5%. Here is my source: http://neutrino.aquaphoenix.com/un-esa/sun/sun-chapter4.html

Unfortunately the very first line on that source is not correct.

The Sun shines because of the process of fusion...

The sun does NOT shine because of fusion. The sun shines because it is hot. Fusion is a by-product and replenishes lost energy so that the sun may shine for a long time, but fusion doesn't cause the sun to shine.

I'm suspicious of the rest of the page as well... Most of the references are 10-20 years old. I think qraal's answer covered it. The temp and pressure must reach a critical value before helium fusion starts, and if I remember right this is very much a sudden process, hence the 'helium flash.'

Some of the more experienced members might be able to correct me though, if I have misunderstood this concept.
 
  • #26
Vanadium 50 said:
If two stars have the same temperature and luminosity, they *must* have the same size. That's a consequence of stars being blackbodies, and has nothing to do with any energy generating mechanism.

Not true. Stars are not black bodies. You can approximate the output of a star by a black body to get a rough approximation, but they aren't. In particular, population II stars have heavy iron lines that cause their energy distribution to be wildly different than population I stars.

One problem here is that you end up with multiple definitions of "temperature", "luminosity" and "radius." You can *define* an effective temperature which is the temperature the star would have if it were a black body with the radius being the photosphere, but that effective temperature can be quite different from temperature defined some other way (for example, if you try to curve fit the spectrum against a BB spectrum).

Wikipedia does a good job explaining it

http://en.wikipedia.org/wiki/Effective_temperature
http://en.wikipedia.org/wiki/Color_temperature
http://en.wikipedia.org/wiki/Brightness_temperature

Also in astronomy the term luminosity is qualified with the wavelength of the luminosity. Bolometric luminosity is the totally energy output of the star at all wavelengths. Also talking about the "radius" of the star gets you into interesting questions. Stars are gaseous which means that there isn't a hard surface like there is on the earth. What people talk about when they talk about radius is the photosphere which is the point at which the star becomes opaque.
 
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  • #27
There is no good way to calculate the size of a stars photosphere based on luminosity that I know of - too many variables.
 
  • #28
turboguppy said:
The sun does NOT shine because of fusion. The sun shines because it is hot. Fusion is a by-product and replenishes lost energy so that the sun may shine for a long time, but fusion doesn't cause the sun to shine.

That's a semantic thing. If you turn off the fusion engine, the sun will go cold after a few thousand years.

I'm suspicious of the rest of the page as well... Most of the references are 10-20 years old.

Yup, but most of the processes were worked out in the 1940's, and solar mass nucleosynthesis hasn't changed in 10-20 years. The one place where the page is out of date is the last paragraph where it talks about the solar neutrino problem which has been solved.
 
  • #29
CoolYoungStar said:
First, helium most certainly burns in the sun; however, the core is not hot enough to support large amounts of this cycle. I believe the p-p chain is responsible for 98% of the suns energy while the CNO is second with ~1.5%.

The problem is that CNO is a hydrogen-burning cycle not a helium burning one.
 
  • #30
~jet said:
I wasn't as certain about is what is there that prevents a little helium from being fused along the way prior to the formation of the first helium core? I have some difficulty perceiving the mechanisms by which, SNAP, all of a sudden a helium core spontaneously exists.

Ignition temperature. A lot of these processes are very sensitive to temperature which means that if you are below a threshold, nothing happens, but once you cross it, the reaction rate increases by a huge amount. What's more the reactions release energy which cause everything to increase even more.

A good analogy is cooking oil. If you keep the oil below a critical temperature, nothing happens to it, but once you cross the limit, it smokes and ignites.

So the heavier material sinks; that makes sense... it accumulates... does it reach, maybe, some critical mass where it begins to fuse?

Critical temperature/pressure.

It just seems to me that at the center of a star, given higher temps and pressures, some of it would be fusing prior to the formation of a shell.

Depending on how hot the center is, it doesn't hit the critical temperatures.

We should all go dissect a star. =) I don't think the natives will mind.

Been done. Google for helioseismology and astroseismology
 
  • #31
Also there are two H-R diagrams. Theorists work with bolometric luminosity versus effective temperature. You run the computer model, that gives you energy output and a radius were pressure goes to zero, you then calculate an effective temperature.

Observers work with color versus absolute magnitude. You measure the brightness of the star with two colored filters and plot on one axis, you take the visual magnitude correct for distance, plot on the other axis.

These two scales are roughly the same, but if you want to do precision work, then you have to apply all sorts of correction terms. In the observers diagram you are measuring color temperature whereas in the theorists diagram, you are measuring effective temperature. People go spend a ton of effort getting all this right, see..

http://iopscience.iop.org/1538-3881/120/2/1072/990160.text.html

The pattern in which everything becomes more complicated when you look at it closely is common thing in astronomy. For example if I ask you want time is it, do you mean TCG, TCG, UT, or TAI?
 
  • #32
Vanadium 50 said:
Rishavutkarsh, I am sorry, but none of that is true. The luminosity of a star is determined by its radius and temperature.

Luminosity in what energy band? A star isn't a blackbody of course, it has a distribution of temperatures and opacities at different depths and so does not have a single defined "temperature" and "surface".
 
  • #33
Chronos said:
There is no good way to calculate the size of a stars photosphere based on luminosity that I know of - too many variables.

What I am most interested in is having an acceptable approximation of luminosity, radius, surface temperature (and thus color) based on initial mass and approximate age. I'm not coming at the problem based on observed stars, but on initial mass.

Someone else 'round here mentioned metallicity influencing the visible output/temperature of a star, and that seems fair... but to what level? a percent? Are there terms I can research that would lead to understanding or measuring likely metallicity based on initial environment? or to what effect and degree their presence incurs?
 
  • #34


I have been finding formula's for just about everything about stars and
was wondering if core and surface temperature has a formula as well?

Its 2,771,043 for the Sun as an example.( core / surface)kelvin.


Thanks
Bob
 

1. What is the relationship between a star's luminosity, temperature, and mass?

The luminosity, temperature, and mass of a star are all related through the star's luminosity-mass-temperature relationship. This relationship states that a star's luminosity is directly proportional to its mass and the fourth power of its temperature. In other words, the more massive and hotter a star is, the more luminous it will be.

2. How are a star's luminosity, temperature, and mass measured?

A star's luminosity can be measured by observing its brightness and distance from Earth. Its temperature can be determined by analyzing its spectrum, and its mass can be calculated using the star's luminosity-mass-temperature relationship and other physical properties such as its radius and surface gravity.

3. What factors affect a star's luminosity, temperature, and mass?

The main factors that affect a star's luminosity, temperature, and mass are its initial mass, composition, and stage of evolution. Other factors that can have an impact include its rotation, magnetic fields, and interactions with other stars in a binary or multiple star system.

4. How do changes in a star's luminosity, temperature, and mass affect its lifespan?

A star's luminosity, temperature, and mass are all closely linked to its energy production and consumption. Changes in any of these properties can affect the rate at which a star burns its fuel, and therefore, its lifespan. For example, a more massive star will have a shorter lifespan than a less massive star because it burns through its fuel at a faster rate.

5. Can a star's luminosity, temperature, and mass change over time?

Yes, a star's luminosity, temperature, and mass can change over time as it goes through different stages of its evolution. For example, as a star exhausts its fuel, its luminosity and temperature may decrease, and its mass may change due to processes such as mass loss through stellar winds or accretion from a companion star.

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