Effect of Temperature Difference on Thermal Contact Conductance

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The discussion focuses on the effect of temperature difference on thermal contact conductance between two identical bodies. When one body is heated to 100 degrees Celsius and the other to 0 degrees Celsius, they reach equilibrium at 50 degrees Celsius in about 10 seconds. If the first body is heated to 1000 degrees Celsius, the time to reach equilibrium remains approximately the same at 10 seconds, as heat transfer is directly proportional to the temperature difference. The conversation also clarifies that while fluid velocity is related to the square root of pressure difference, heat transfer operates on a linear relationship with temperature difference. The insights provided helped clarify misconceptions about heat transfer dynamics.
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Hi, I'm new to this forum.

A colleague and me have a discussion in heat transfer between to bodies (thermal contact conductance)

Let's say yo have a body A and B (witch are identical), A is heated to a hundred degree Celsius, B is 0 degree Celsius. You then put the bodies A and B together. You record that the it took 10 seconds before the bodies A and B are at the same temperature (50 degrees Celsius).

You now to the same experiment again, but this time body A is heated to 1000 degrees Celsius, will it then take 100 seconds before body A and B are at the same temperature?

Sorry for my bad English :) I hope someone will reply?
 
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Welcome to PF!

The answer is approximately the same 10 sec. If you graph the temperature change it will look like a hyperbola, with the initial slope being a direct proportion of the temperature difference. So 10x larger DT means 10x faster heat transfer.

I say "approximately" though because mathematically they never actually reach equilibrium and you have to arbitrarily decide how close is close enough.
 
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Thank you russ watters for the answer :) so the "flow" of energy is like to vessels with pressure interconnected with a pipe and a valve, when the valve opens, the flow is equal to the square of the differential pressure? f=Sqr(P2-P1) ?
 
Sorry, that's a no on both counts: velocity in fluids is a square ROOT function of pressure (doubling DP yields a 1.4x increase in flow -- your equation was right but you said it wrong) but heat transfer is a direct/exact proportion (doubling DT doubles heat flow).

(Mod note: moved to mech - e)
 
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Tank you Russ Watters :) You saved me and my coworker a lot of discussion
 
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