A rock rolling down an incline-velocity and force

AI Thread Summary
To calculate the velocity of a 20-ton spherical rock rolling down a 400-meter incline, the conservation of energy principle is applied. Initially, the rock possesses gravitational potential energy, which converts to kinetic energy as it reaches ground level. The velocity can be determined using the formula derived from energy conservation, where potential energy equals kinetic energy. Additionally, the force exerted on the rock can be calculated using Newton's second law, factoring in its mass and acceleration. Understanding these concepts is crucial for solving the problem accurately.
NDbogan
Messages
18
Reaction score
0
The question is:
a spherical rock weighing 20 tons starts rolling down a steep incline from a height of 400 metres. Calculate the velocity when it reaches the ground level. What is the force exerted on the rock?


I've tried to work this out but I just can't seem to grasp exactly what I'm missing.

Any help will be really appreciated.
 
Physics news on Phys.org
Conservation of energy ::biggrin::
 
hmm...could you explain it a bit further.
 
Use conservation of energy. The energy the rock has at the start and what is the energy converted to when it reaches the bottom
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top