A seemingly difficult differential equation

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Homework Help Overview

The discussion revolves around a differential equation related to an engineering problem, specifically involving the expression \(\frac{a+bsinwt-c\sqrt{H}}{k}=\frac{dH}{dt}\). Participants are exploring methods to solve this equation, including potential solutions and specific cases.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various approaches to solving the differential equation, including the use of software like Maple. There are attempts to simplify the problem by considering special cases, such as when \(b=0\) or \(a=0\). Questions arise regarding the implications of these cases on the overall solution.

Discussion Status

The discussion is ongoing, with some participants providing potential solutions while others express the complexity of the problem. There is no explicit consensus on a single solution, and multiple interpretations of the equation are being explored.

Contextual Notes

Participants note that certain parameters, such as \(b\), cannot be zero, which influences the nature of the solutions being discussed. The original poster indicates a need for a solution applicable to a specific engineering context, adding to the complexity of the discussion.

hanson
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Anyone know how to solve it?
Either step by step or using MatLab/Mathematica/Maple is ok.
[tex]\frac{a+bsinwt-c\sqrt{H}}{k}=\frac{dH}{dt}[/tex]

I need it in modelling an engineering problem, but I simply don't have any idea to solve it...
 
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the solution is approaching ulgy

Maple and I can only solve it if b=0.

It is easy for a=b=0, e.g. the homogeneous case, namely

[tex]k\frac{dH}{dt}+c\sqrt{H(t)}=0[/tex]

has the solution

[tex]H(t)=(C-\frac{ct}{2k})^2[/tex].

If [tex]a\neq 0,[/tex] then the solution is approaching ulgy, see for yourself: Implicitly it is given by

[tex]c^2t+ka\ln(-a^2+c^2H(t))+2ck\sqrt{H(t)}-ka\ln(a+c\sqrt{H(t)})+ka\ln(c\sqrt{H(t)}-a)+C = 0[/tex]

have a nice day
 
Last edited:
thanks
but b cannot be zero.
anyone have more?
 
I think that a solution is as follows:

H = ( a/c + (H0^2-a/c)exp(-c/2k t) + b c sin(wt)/(c^2+4*k^2*w^2) - 2 k b w cos(wt)/(c^2+4*k^2*w^2) )^2
 
Last edited:

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