A simple confusion: Showing projectile is launched horizontally

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SUMMARY

The discussion centers on the trajectory equation of a ball projected horizontally, specifically y = -0.05x^2. The key conclusion is that the angle of projection, denoted as 'a', is zero, confirming horizontal launch. This is derived from the relationship x tan a = 0, where the derivative of the function at x=0 is zero, indicating that the tangent of the angle is also zero. Thus, the ball is indeed projected horizontally.

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Faiq
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The equation of trajectory of ball B is y = -0.05x^2 where y is vertical displacement and x is horizontal. Prove that the ball is projected horizontallyFor this, the mark scheme says
x tan a = 0 so a =0
Since the angle between ball and surface is 0 the object is projected horizontally.
I can't work out how is x tan a = 0
 
Last edited:
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The problem statement got lost somehow.
 
Please check again
 
I don't see where the x would come from.

tan a is the derivative of your function at x=0. The derivative is 0, therefore tan a = 0.
 
How do you know the derivative is 0?
 
Got it thanks
 

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