A "spiral" in the Complex plane

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SUMMARY

The discussion centers on the convergence of the series representing a "spiral" in the complex plane, specifically the series 1+i-1/2-i/3!+1/4!+i/5!-1/6!-i/7!... This series can be separated into its real and imaginary components, with the real part represented by the series 1-1/2+1/4!-1/6!... and the imaginary part by 1-1/3!+1/5!-1/7!... The key functions involved are the Taylor series for cosine and sine, specifically ∑_{n=0}^∞ (-1)^n x^{2n} / (2n)! for cosine and ∑_{n=0}^∞ (-1)^n x^{2n+1} / (2n+1)! for sine, evaluated at x=1.

PREREQUISITES
  • Understanding of complex numbers and the complex plane
  • Familiarity with Taylor series and their convergence
  • Knowledge of the sine and cosine functions as infinite series
  • Basic calculus concepts, particularly series and limits
NEXT STEPS
  • Study the Taylor series expansion for cos(x) and sin(x) in detail
  • Explore convergence criteria for infinite series in complex analysis
  • Investigate the properties of complex exponentials and their relation to trigonometric functions
  • Learn about the geometric interpretation of complex series in the complex plane
USEFUL FOR

Mathematicians, physics students, and anyone interested in complex analysis and series convergence will benefit from this discussion.

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Homework Statement
Starting from the origin, go one unit east, then the same length north, then (1/2) of the previous length west, then (1/3) of the previous length south, then (1/4) of the previous length east, and so on. What point does this “spiral” converge to?
Relevant Equations
series sum
I understand that the "spiral" converges to 1+i-1/2-i/3!+1/4!+i/5!-1/6!-i/7!... .
It splits into two: one for Re, 1-1/2+1/4!-1/6!..., and the other for Im, 1-1/3!+1/5!-1/7!... .
Any hints on how to compute them?
 
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What are <br /> \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n}}{(2n)!} and \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n+1}}{(2n+1)!} when x = 1?
 
pasmith said:
What are <br /> \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n}}{(2n)!} and \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n+1}}{(2n+1)!} when x = 1?
##\cos## and ##\sin##, of course. Thanks!
 
Or, even better:
$$
\sum_{n=0}^\infty \frac{(ix)^n}{n!}
$$
 
Orodruin said:
Or, even better:
$$
\sum_{n=0}^\infty \frac{(ix)^n}{n!}
$$
Yes. Straight.
 

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