A "spiral" in the Complex plane

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The discussion centers on the convergence of a spiral in the complex plane, specifically to the value 1+i-1/2-i/3!+1/4!+i/5!-1/6!-i/7!.... It is noted that this series can be separated into real and imaginary components, with the real part represented by the series 1-1/2+1/4!-1/6!... and the imaginary part by 1-1/3!+1/5!-1/7!.... Participants seek methods to compute these series and inquire about the values of specific sums involving factorials at x=1, which relate to the cosine and sine functions. The conversation highlights the connection between these series and the exponential function expressed as a power series. Understanding these relationships is crucial for further exploration of complex analysis.
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Homework Statement
Starting from the origin, go one unit east, then the same length north, then (1/2) of the previous length west, then (1/3) of the previous length south, then (1/4) of the previous length east, and so on. What point does this “spiral” converge to?
Relevant Equations
series sum
I understand that the "spiral" converges to 1+i-1/2-i/3!+1/4!+i/5!-1/6!-i/7!... .
It splits into two: one for Re, 1-1/2+1/4!-1/6!..., and the other for Im, 1-1/3!+1/5!-1/7!... .
Any hints on how to compute them?
 
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What are <br /> \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n}}{(2n)!} and \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n+1}}{(2n+1)!} when x = 1?
 
pasmith said:
What are <br /> \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n}}{(2n)!} and \displaystyle\sum_{n=0}^\infty \dfrac{(-1)^n x^{2n+1}}{(2n+1)!} when x = 1?
##\cos## and ##\sin##, of course. Thanks!
 
Or, even better:
$$
\sum_{n=0}^\infty \frac{(ix)^n}{n!}
$$
 
Orodruin said:
Or, even better:
$$
\sum_{n=0}^\infty \frac{(ix)^n}{n!}
$$
Yes. Straight.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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