- #1
jinksys
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Homework Statement
Integral Sqrt[16-x^2]*x dx from 0 to 2.
Homework Equations
The Attempt at a Solution
First thing I do is a u-sub, so
u=16-x^2
du=-2xdx
I also my bounds change to upper=12 lower=16.
After I integrate and swap out my U, I get
-1/3*(16-x^2)^(3/2) from 16 to 12.
Am I using the wrong method?