AAt Invertibility: Implications for A Inverse

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Homework Statement



Show that if AAt(where At is the transpose of A) has no inverse,Then A itself cannot have an inverse

2. The attempt at a solution

Here's what i did

AAt.(AAt)-1=AAt.At-1A-1=AA-1=I

thus AAt has an inverse IF and only IF A is invertible and since AAT has no inverse then A has no inverse ...

i thinkt it's somehow wrong the teacher told me that i assumed that AAt is invertible but it's given without an inverse ..any suggestions would be appreciated :)
 
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JosephR said:

Homework Statement



Show that if AAt(where At is the transpose of A) has no inverse,Then A itself cannot have an inverse

2. The attempt at a solution

Here's what i did

AAt.(AAt)-1=AAt.At-1A-1=AA-1=I

thus AAt has an inverse IF and only IF A is invertible and since AAT has no inverse then A has no inverse ...

i thinkt it's somehow wrong the teacher told me that i assumed that AAt is invertible but it's given without an inverse ..any suggestions would be appreciated :)

You've assumed it's invertible by writing down (AAT)-1

Hint: Consider determinants...
 
i haven't taken determinant till now.. is there any other way to do it ?
 
You want to prove "If AAT does NOT have an inverse, then A itself does NOT have an inverse". With all those "not"s, that's what I would call a "negative" statement. It is almost easier to prove the contraposative of a "negative" statement than the statement itself because then you can make a "positive" statement.

Here the contrapositive is "If A has an inverse then so does AAT."
 
you mean i should assume that A is invertible and prove that AAT is invertible also ...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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