- #1
maxpayne_lhp
- 36
- 0
Hello,
Well, I have the equation:
[tex]x^2-2x-m|x-1|+m^2=0 (1)[/tex] They ask me what m is so that the equation has solution(s)
Well, I let [tex]t=|1+x|[/tex] and solve the problem with t (no more x) and I have the last equation: [tex]t^2-mt+m^2-1=0[/tex] (2)
in order that (1) has solution(s), (2) must have solution(s) t grater or equal 0
Is that right?, is the action of let t is something make my solution wrong?
Thanks
Well, I have the equation:
[tex]x^2-2x-m|x-1|+m^2=0 (1)[/tex] They ask me what m is so that the equation has solution(s)
Well, I let [tex]t=|1+x|[/tex] and solve the problem with t (no more x) and I have the last equation: [tex]t^2-mt+m^2-1=0[/tex] (2)
in order that (1) has solution(s), (2) must have solution(s) t grater or equal 0
Is that right?, is the action of let t is something make my solution wrong?
Thanks