Absolute Error of a Given Function

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SUMMARY

The discussion centers on calculating the absolute error for the function f = (xy/z) + 5w. The user successfully derived the partial derivatives: df/dw = 5, df/dx = y/z, df/dy = x/z, and df/dz = (-xy)/z. To compute the absolute error, the user must substitute these derivatives into the absolute error equation: (df)^2 = (df/dw)^2(dw)^2 + (df/dx)^2(dx)^2 + (df/dy)^2(dy)^2 + (df/dz)^2(dz)^2. The next step involves plugging in the values for the differentials to find the total absolute error.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with error analysis in calculus
  • Knowledge of multivariable functions
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Practice calculating absolute error for different multivariable functions
  • Learn about Taylor series expansions for error approximation
  • Explore numerical methods for error analysis
  • Study the implications of error propagation in engineering applications
USEFUL FOR

Students in calculus, engineers performing error analysis, and anyone interested in understanding the implications of error in multivariable functions.

rushton_19
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Homework Statement



Find the absolute error for the following function:

f = (xy/z)+5w


Homework Equations



Equation for an error vector:
df = (df/dw)dw + (df/dx)dx + (df/dy)dy + (df/dz)dz

Equation for the absolute error:
(df)^2 = (df/dw)^2(dw)^2 + (df/dx)^2(dx)^2 + (df/dy)^2(dy)^2 + (df/dz)^2(dz)^2


The Attempt at a Solution



I found what I hope are the correct partial derivatives :

df/dw = 5

df/dx = y/z

df/dy = x/z

df/dz = (-xy)/z

I just don't know what to do now that I've found the partial derivatives. Do I just substitute it into my second equation, or are there more steps after that?

Thanks!
 
Physics news on Phys.org
double check all of your derivatives, and then yes, the next steps are plug and play.
 

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