AC Voltage Waveform: Frequency, Time, RMS & Instantaneous Value

AI Thread Summary
The discussion centers on solving an AC voltage problem defined by the equation v(t) = 100 sin(250πt). Key points include calculating the frequency, time for one complete cycle, instantaneous voltage at 6ms, RMS value, and the first occurrence of 50V after t=0ms. A participant seeks clarification on the discrepancy between their calculations and a textbook example, specifically regarding the sine function's input values. The confusion stems from using different coefficients in the sine function, leading to different results, but the participant ultimately resolves their misunderstanding. The thread highlights the importance of correctly interpreting the waveform parameters in AC voltage calculations.
cschear87
Messages
25
Reaction score
0

Homework Statement



Given an AC Voltage that varies in time according to the equation:

v(t) = 100 sin(250t)

(i) What is the frequency of this waveform?

(ii) Calculate the time for one complete cycle of the voltage?

(iii) Calculate the instantaneous value of the voltage at time = 6ms.

(iv) Calculate the Root-Mean Square (RMS) value of the AC voltage.

(v) The first time after t=0ms that the instantaneous voltage is 50V.


Homework Equations



v(t) sin (250 x 6 x 10^-3)

The Attempt at a Solution



I'm trying to, obviously, get the third part of this. What I have so far is:
100sin (250pi x 6 x 10^-3)
=100sin (4.71)
In an example in my book it then goes on to multiply 100 x .951... where does the .951 come from and is this what I use for this equation or should I use a different number?
The equation in the book I have is (still 6ms):
v(t) = 100sin (100pi t) V
Their solution is:
100 sin (100pi x 6 x 10^-3)
=100sin (1.88)
=100 x .951
=95.1V
Not sure what I'm missing?
 
Physics news on Phys.org
It looks like they are using ##100\pi## instead of the ##250\pi##. Probably a typo somewhere.
 
The equation in the book I have is (still 6ms):
v(t) = 100sin (100pi t) V
Their solution is:
100 sin (100pi x 6 x 10^-3)
=100sin (1.88)
=100 x .951
=95.1V


sin(1.8849) = 0.951 if using radians.

In your problem (which is different to the one in the book) you use a different number eg..

= 100sin(4.71)
 
CWatters said:
sin(1.8849) = 0.951 if using radians.

In your problem (which is different to the one in the book) you use a different number eg..

= 100sin(4.71)

OH I see, just got confused. Thank you!
 
Back
Top