Accelaration/ traveling problem

  • Thread starter Teenytiny1991
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    Accelaration
In summary, a camero ran a red light and hit an SUV while a TV news crew was filming. The sound of squealing tires recorded on film allowed police to determine that the driver applied his brakes for 1.69 seconds. After reviewing the clip, a CSI team determined that the car decelerated at a constant rate of -10.2 m/s^2 for a distance of 48.2 meters before impact. Using this information, the camero's initial speed can be calculated to be 27.8 m/s and its speed upon impact was 11.25 m/s.
  • #1
Teenytiny1991
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Homework Statement


A camero runs a red light and hits an suv directly behind where a tv news crew is filming. from the sound of the dqueling tires recorded on film, the police can tell that the driver applied his breaks for exactly 1.69 secs. a csi team review the clip and determines the care decelerated at a constant rate of -10.2 m/s^2 prior to the impact. the skid marks determined he breaked for 48.2 meters
A) how fast was the camero going before the driver applied the breaks
B) how fast was the camero traveling when it hit the suv


Homework Equations





The Attempt at a Solution


-10.2 m/s^2 x 1.69 sec/ 48.2 m i don't think i set it up crrectly =(
 
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  • #2
Hi Teenytiny1991! :wink:

(try using the X2 tag just above the Reply box :wink:)

You have a s and t, and you want u and v.

Which of the standard constant acceleration equations should you use?

What do you get? :smile:
 
  • #3

As a scientist, it is important to approach this problem with a systematic and mathematical approach. Let's start by identifying the given information:

- The driver applied the brakes for 1.69 seconds.
- The car decelerated at a constant rate of -10.2 m/s^2.
- The skid marks measured 48.2 meters.

To solve this problem, we can use the equation:

vf = vi + at

Where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time

A) To determine the initial velocity of the camero, we can rearrange the equation to solve for vi:

vi = vf - at

Substituting the given values, we get:

vi = 0 m/s - (-10.2 m/s^2 x 1.69 sec)

vi = 17.238 m/s

Therefore, the camero was traveling at 17.238 m/s or approximately 61.66 km/h before the driver applied the brakes.

B) To determine the velocity of the camero when it hit the suv, we can use the equation:

vf^2 = vi^2 + 2ad

Where:
vf = final velocity
vi = initial velocity
a = acceleration
d = distance

Substituting the given values, we get:

vf^2 = (17.238 m/s)^2 + 2(-10.2 m/s^2)(48.2 m)

vf^2 = 296.966 m^2/s^2

vf = √296.966 m^2/s^2

vf = 17.238 m/s

Therefore, the camero was traveling at 17.238 m/s or approximately 61.66 km/h when it hit the suv.

In conclusion, the camero was traveling at a speed of 61.66 km/h before the driver applied the brakes and maintained the same speed when it hit the suv. It is important to note that this is a simplified calculation and does not take into account other factors such as friction and air resistance.
 

1. What is acceleration?

Acceleration is the rate of change of velocity. It measures how quickly an object's velocity is changing, either by increasing or decreasing.

2. What are the units of acceleration?

The units of acceleration are typically meters per second squared (m/s^2) in the metric system, or feet per second squared (ft/s^2) in the imperial system.

3. How is acceleration related to velocity and time?

Acceleration is directly related to velocity and time through the formula a = Δv/Δt, where a is acceleration, Δv is change in velocity, and Δt is change in time. This means that an object's acceleration is determined by how much its velocity changes over a certain amount of time.

4. How does acceleration affect an object's motion?

Acceleration affects an object's motion by causing it to speed up, slow down, or change direction. An object with no acceleration will continue to move at a constant velocity, while an object with non-zero acceleration will experience a change in its velocity.

5. What is the difference between acceleration and deceleration?

Acceleration and deceleration are both changes in velocity, but they have opposite effects. Acceleration is an increase in velocity, while deceleration is a decrease in velocity. Both can be described using the same formula, a = Δv/Δt, but the sign of the change in velocity will be positive for acceleration and negative for deceleration.

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