Accelerated Physics Homework Help

  • Thread starter Leo34005
  • Start date
  • #1
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Homework Statement



A boy sledding down a hill accelerates at 1.45 m/s2. If he started from rest, in what distance would he reach a speed of 7.60 m/s?

Homework Equations



(vf)^2 = (vo)^2 + 2ax
where vf = final velocity = 7.6 m/s
vo = initial velocity = 0 m/s
a = 1.45 m/s2

x = distance = unknown

The Attempt at a Solution



a = 1.45 m/s
Vf = 7.60 m/s
Vo = 0 m/s

(7.60)^2 = (0)^2+2(1.45)(x)
15.2 = 0 + 2.9x
15.2 = 2.9x
5.143 = x
 

Answers and Replies

  • #2
G01
Homework Helper
Gold Member
2,665
16
You made a computation error:

7.6^2 is not 15.2

7.6^2=7.6 X 7.6 = 57.76
 

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