Accelerated Physics Homework Help

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SUMMARY

The discussion focuses on a physics problem involving a boy sledding down a hill with an acceleration of 1.45 m/s², starting from rest, and reaching a final speed of 7.60 m/s. The relevant equation used is (vf)² = (vo)² + 2ax, where vf is the final velocity, vo is the initial velocity, a is acceleration, and x is the distance. The initial calculation incorrectly stated that 7.6² equals 15.2, while the correct value is 57.76. The correct distance x, calculated using the proper value, is approximately 5.143 meters.

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Homework Statement



A boy sledding down a hill accelerates at 1.45 m/s2. If he started from rest, in what distance would he reach a speed of 7.60 m/s?

Homework Equations



(vf)^2 = (vo)^2 + 2ax
where vf = final velocity = 7.6 m/s
vo = initial velocity = 0 m/s
a = 1.45 m/s2

x = distance = unknown

The Attempt at a Solution



a = 1.45 m/s
Vf = 7.60 m/s
Vo = 0 m/s

(7.60)^2 = (0)^2+2(1.45)(x)
15.2 = 0 + 2.9x
15.2 = 2.9x
5.143 = x
 
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You made a computation error:

7.6^2 is not 15.2

7.6^2=7.6 X 7.6 = 57.76
 

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