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Accelerated Physics Homework Help

  1. Aug 30, 2009 #1
    1. The problem statement, all variables and given/known data

    A boy sledding down a hill accelerates at 1.45 m/s2. If he started from rest, in what distance would he reach a speed of 7.60 m/s?

    2. Relevant equations

    (vf)^2 = (vo)^2 + 2ax
    where vf = final velocity = 7.6 m/s
    vo = initial velocity = 0 m/s
    a = 1.45 m/s2

    x = distance = unknown

    3. The attempt at a solution

    a = 1.45 m/s
    Vf = 7.60 m/s
    Vo = 0 m/s

    (7.60)^2 = (0)^2+2(1.45)(x)
    15.2 = 0 + 2.9x
    15.2 = 2.9x
    5.143 = x
     
  2. jcsd
  3. Aug 30, 2009 #2

    G01

    User Avatar
    Homework Helper
    Gold Member

    You made a computation error:

    7.6^2 is not 15.2

    7.6^2=7.6 X 7.6 = 57.76
     
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