Accelerated Physics Homework Help

[Leo34005]

Homework Statement

A boy sledding down a hill accelerates at 1.45 m/s2. If he started from rest, in what distance would he reach a speed of 7.60 m/s?

Homework Equations

(vf)^2 = (vo)^2 + 2ax
where vf = final velocity = 7.6 m/s
vo = initial velocity = 0 m/s
a = 1.45 m/s2

x = distance = unknown

The Attempt at a Solution

a = 1.45 m/s
Vf = 7.60 m/s
Vo = 0 m/s

(7.60)^2 = (0)^2+2(1.45)(x)
15.2 = 0 + 2.9x
15.2 = 2.9x
5.143 = x

 

[G01]

You made a computation error:

7.6^2 is not 15.2

7.6^2=7.6 X 7.6 = 57.76

 

[tomcue]

The boy will reach a speed of 7.60 m/s in approximately 5.143 meters. This calculation assumes that the acceleration remains constant throughout the entire distance traveled, which may not be the case in real-world scenarios. In addition, it is important to consider other factors such as air resistance and the mass of the sled, which could affect the acceleration and ultimately the distance traveled. Overall, this problem demonstrates the application of the basic kinematic equation for constant acceleration and highlights the importance of considering all relevant factors when solving physics problems.