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habibclan
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Homework Statement
A particle moves in the xy-plane with constant acceleration. The particle is located at r= (2i + 4j)m at t=0 s. At t=3 s it is at r=(8i - 2j) m and has a velocity v= ( 5i - 5j) m/s.
a) What is the particle's acceleration vector a?
b) What are its position, velocity and speed at t= 5s?
Homework Equations
xf= xo + vt+ 0.5 a t^2
yf= yo + vt+ 0.5 a t^2
The Attempt at a Solution
I used the above two equations to solve for the acceleration in both x and y components separately and I got a= (1.33i - 1.33j), but the answer at the back of the textbook is a= (2i - 2j). I don't understand what I'm doing wrong. Can someone guide me please? Thanks in advance!