Mike_Fontenot said:
You are right. Immediately after Tom's instantaneous speed change, Sue is -4.6 years old (according to Tom)...i.e., Sue's mother-to-be will age another 4.6 years before she gives birth to Sue.
Fredrik said:
. Also, I think Mike meant that 0 time has elapsed on Tom's clock at the event we're supposed to consider.
I don't feel like doing any calculations right now, but in the diagram I'm drawing in my head, I can see that Sue would be much younger than 30 in Tom's comoving inertial frame (after the boost), because its simultaneity lines have slope v in the diagram, so the boost event is simultaneous with an "early" event on Sue's world line.
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Mike_Fontenot said:
Suppose two people (say, Tom and Sue) are stationary with respect to one another, when they are both 30 years old, and that they are 40 lightyears apart.
Then suppose that Tom instantaneously changes his speed so that he is moving away from Sue at 0.866c.
Austin0 said:
.
Prior to Tom's acceleration his frame mate Bob is vacationing at rest 26 ly towards earth.
As Tom initiates acceleration Bob is rudely awaken only to get a last fleeting glimpse of the Earth rushing towards him due to the Earth frame's contraction.
Not only terminating Bob but incidently nailing Sue's mom on the way to the library.
My question is this : ...Does Tom simultaneously lose all memory of Sue or does he wait until the information regardiung her prenatal demise (i.e. history) reachs him at c ?
What does CADO predict?? :-)
Fredrik said:
Did you really? In which one of his frames? The comoving inertial frame before the boost? The comoving inertial frame after the boost? The radar frame? Why would Bob wake up because someone 26 light-years away is accelerating rapidly? Why would that Lorentz contract the Earth and make him teleport to Earth, nail Sue's mom, teleport back and die? Like I said, your description makes no sense.
Sorry...as I said this was basically a joke. A play on the artificial paradox made possible by the assumption of instantaneous acceleration and resulting instantaneous shifting of simulataneity lines and relative coordinates.
It was not a puzzle or question regarding figuring out those coordinate changes . I assumed that you and most people given the context of this thread would be able to do it in your head or with simple calculation based on the gamma factor. Just as you did in your head the post above.
I also made some assumptions within this contaxt that now appear to be ambiguous.
I assumed that "Toms frame mate Bob" would be taken as Bob at rest in the
same frame as Tom. Not Bobs comoving frame was at rest with Toms comoving frame as
two separate entities.
Here is the real ambiguity I didn't make clear that Bob unlike SUe was attached to the boosted frame. I assumed from the context and what happened to Bob this would be implicit.
My mistake. Oops
I also assumed the interpretation would be that when this frame was accelerated this would apply to both locations and both people instantaneously.. Without going into details of Born rigid acceleration etc.
SO given an instantaneous change. . Bobs position wrt Tom and his own frame do not change with the boost. Only the relative simultaneity and contraction of the Earth frame.
In Bob and Toms frame the Earth is suddenly closer by the gamma factor . In this case the new position is now between Bob and Tom. The Earth having to pass through Bobs location (and Bob) to get there. No teleportation on Bob's part required.
AS I said the joke was in in the question at the end. I assumed these calculations were trivial and obvious. ANd not to be taken seriously. I am not suggesting that length contraction actually implies a physical translation. I also assumed it would be obvious this was a joke both by the question and the language of the setup.
I now realize I was wrong on all counts. My communication software still needs major upgrade.
On a more serious note: I am not familiar with Mike_Fontenot's program and how it might correlate wht radar methods etc.
But from what I have gotten from his explanation of the basis I would have to agree.
In all cases calculations
based on the frame itself must correspond with any results from lines of simulataneity. SPecifically :SImply assuming the frame extended in space to include the point in the other frame and applying the Lorentz tranforms you can derive the spatial coordinate of the proximate observer (virtual) in your frame and the clock time in the other.
This is an assumption I have operated on for years. From this perspective in my mind I derived the correct answer to Mike's question by simply multiplying the 40 ly distance by velocity , Since I did it in my head I only got an approximate answer but a quick calculation on paper would have returned the exact answer but I didn't feel like the effort.
To check my assumption; last year I ran it by DrGreg and now have a thread going to get further feedback. SO far I have gotten no reason to doubt this assumption.
If see any reason for doubt; the thread is frames vs lines of simultaneity.
I will try to be clearer and more explicit in the future. Thanks