Acceleration down an inclined plane

AI Thread Summary
Acceleration down an inclined plane should theoretically be inversely proportional to mass, but experimental data showed a direct proportionality. The discussion highlights the confusion around the relationship, emphasizing that according to Newton's second law (F=ma), an increase in mass should lead to decreased acceleration. The net force acting on the container is influenced by gravity and the angle of the incline, which complicates the expected outcomes. Additionally, the absence of a friction coefficient in the analysis may contribute to the unexpected results. Understanding these factors is crucial for accurately interpreting the experiment's findings.
Worfie
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Hello,

After collecting data for the classic physics experiment - motion down an inclined plane, I assembled my graph, and found something startling; in my graph, acceleration is proportional to mass (use the attached file for reference).

Theoretically, my graph should resemble the inverse, by a ∝ 1/m.

Can anyone explain possible reasons for this?

The experiment was running a margarine container down a wooden slope, varying the mass of the margarine container by adding brass weights each time.
 

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Worfie said:
Theoretically, my graph should resemble the inverse, by a ∝ 1/m.

What makes you think so?
 
F=ma, therefore a=F/m, which implies as the mass increases, acceleration decreases.
 
What is F in your case?
 
F=mg(sinθ-cosθ)

where θ is the angle of the inclined plane.

This is the net force of the block down the plane.
 
And inserting this into your expression for the acceleration gives?

Edit: you are also missing a friction coefficient...
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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