Acceleration Due to Gravity Question

AI Thread Summary
When an object is thrown straight downward, its acceleration remains at -9.8 m/s², assuming no aerodynamic drag and a negligible distance from Earth. The initial velocity affects the object's speed but does not change the acceleration due to gravity once it is in free fall. Thrust is considered a force acting against the mass of an object, independent of its velocity. In ideal physics scenarios, the only force acting on a free-falling object is gravity, resulting in a constant acceleration of 9.8 m/s². Understanding these principles clarifies the relationship between force, mass, and acceleration in physics.
Cursed
Messages
38
Reaction score
0
Quick question...

If you were to throw an object (such as a baseball) straight downward, would the acceleration of the object still be -9.8m/s/s?
 
Physics news on Phys.org
Ignoring aerodynamic drag, and assuming that the distance from Earth isn't signicantly large, then velcocity doesn't affect the gravitational acceleration.

For a similar example, imagine a rocket in space. It's acceleration is a function of thrust versus mass of the rocket and is also independent of the rockets velocity.
 
Jeff is right, from what I can tell. The initial velocity plays no part in the acceleration of an object in free fall.

Quick question there, Jeff. When you say thrust, are you basically counting it as a 'force' that acts against the mass? I'm relatively new to physics so I'm just trying to understand what I can.
 
Before the object leaves your hand, its acceleration may be higher than gravitational acceleration. But after it comes off your hand, the acceleration is exactly g (not taken air drag into account) because gravity is only force that exerts on.
 
think about it if you throw it straight down its has an initial velocity only. In ideal physics your acceleration due to gravity should be only 9.8m/s on free falling objects.
 
MurdocJensen said:
When you say thrust, are you basically counting it as a 'force' that acts against the mass?
Yes, thrust is simply a force, and doesn't take into account the speed at which the force is applied. Force times speed equals power, for example, force in lbs, times speed in mph, divided by 375 (conversion factor) calculates horsepower.
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top