Acceleration of 4kg Object w/ Force at 37 Degrees

AI Thread Summary
The discussion focuses on calculating the acceleration of a 4 kg object subjected to forces of 50N and 100N at a 37-degree angle. For the 50N force, the calculated acceleration is 10 m/s², which is confirmed as correct. However, when applying the 100N force, the upward net force must be considered, leading to an acceleration of 20.6 m/s² in the upward direction. The importance of factoring in both the x and y components of the force is emphasized for accurate results. Proper application of F=ma is crucial for solving these types of physics problems.
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Homework Statement


Find the acceleration of the object in the figure with mass 4 kg when it's applied a force of a)50N b)100N and which makes an angle of 37degrees.(sin 37=0.6,cos 37=0.8)
[PLAIN]http://img97.imageshack.us/img97/5863/forceg.png

Homework Equations


F=ma

The Attempt at a Solution


I have tried to take first Fx=ma for 50N which goes in the direction of x-axis I got 10m/s^2 which is correct but when i try with 100N with Fy=ma I don't get the correct answer.Or with Fx=ma
could you please help me?
 
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When the 100N force is applied, note that there is a net upwards force on the block and hence the block has an upward acceleration. Factor that in and you should get the correct answer.
 
When it applied 100N it should be 20.6m/s^2 upwards direction.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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