Acceleration of a downhill skier

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SUMMARY

The discussion focuses on the correct representation of the weight vector in the context of a downhill skier's acceleration. The weight vector should be denoted as 𝑤 rather than -𝑤, as the latter indicates an opposite direction. The components of the weight vector are defined as Wx = mgsin(27) and Wy = -mgcos(27), with the correct interpretation of their signs being crucial for accurate calculations. Additionally, the diagram must accurately depict Wx as parallel to the x-axis, not horizontal.

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aron silvester

Homework Statement


I understand in my head that Wx = mgsin(27) and Wy = -mgcos(27). Though when I tried solving for both Wx and Wy, their signs turned out to be opposite. I've provided my work leading up to Wx = -mgsin(27) and Wy = mgcos(27). Maybe I interpreted the signs of x and y component of W?
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Homework Equations

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The weight vector should be denoted ##\vec w##, not ##-\vec w##. The vector ##-\vec w## would point in the opposite direction of the weight.

Also, in you diagram, you drew ##\vec w_x## as horizontal rather than parallel to the x axis. (Note that your y component of the weight is larger than the weight w.)
 
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TSny said:
The weight vector should be denoted ##\vec w##, not ##-\vec w##. The vector ##-\vec w## would point in the opposite direction of the weight.

Also, in you diagram, you drew ##\vec w_x## as horizontal rather than parallel to the x axis. (Note that your y component of the weight is larger than the weight w.)
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