A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.0s later.
[itex]v_x = v_0 + at[/itex]
[itex]x_f = x_0 + v_0t + 1/2at^2[/itex]
[itex]v_x^2 = v_0^2 + 2a(Δx)[/itex]
The Attempt at a Solution
The biggest part I'm confused about is whether or not the bolt had an initial positive velocity (I am setting down as negative). It says the bolt "falls off the side", implying it just falls down.
Position of bolt before it falls
[itex]0m = x + 1/2(-9.8m/s^2)(6.0s)^2[/itex]
[itex]x_i = 176.4m[/itex]
Acceleration of rocket
[itex]176.4m = 1/2(a)(4.0s)^2[/itex]
[itex]a = 22.05 m/s^2[/itex]
My answer is incorrect.