Acceleration of Falling Mass Attached to 5cm Pulley

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The discussion revolves around calculating the acceleration of a falling mass attached to a pulley with a 5 cm radius. The initial approach using tension formulas (Mg - T = Ma) was deemed incorrect, leading to the suggestion of using the kinematic equation Y = Yo + (1/2)at^2 instead. Participants note that incorporating the moment of inertia of the pulley is essential for accurate calculations. If the pulley had no moment of inertia, the tension/force method would yield correct results. The conversation highlights the importance of understanding both kinematics and dynamics in solving such physics problems.
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I have a question where there's two masses attached to a pully that has a radius of 5 cm. one mass is heavier than the other one and the first part of the question is asking you to find the acceleration of the mass that's falling (it falls 75 cm in 5 sec). Now the way that i figured it should be done is by using the tension formulas (Mg - T = Ma for the mass falling) however this give the wrong answer, the equation you have to use is Y = Yo +(1/2)at^2. I can;t seem to figure out why you can't use the first method to figure this one out.
 
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hannibal said:
I have a question where there's two masses attached to a pully that has a radius of 5 cm. one mass is heavier than the other one and the first part of the question is asking you to find the acceleration of the mass that's falling (it falls 75 cm in 5 sec). Now the way that i figured it should be done is by using the tension formulas (Mg - T = Ma for the mass falling) however this give the wrong answer, the equation you have to use is Y = Yo +(1/2)at^2. I can;t seem to figure out why you can't use the first method to figure this one out.

To use Newton's second law for such a problem you would have to consider the moment of inertia of the pulley. However, since the acceleration is uniform and you are given the time interval and the displacement, you can just use plain old kinematics \Delta s = at^2/2 and solve for a.
 
Ok I know what the moment of inertia is, however my phys prof had to skip over the last chapter in the book due to time constraints. If there was no moment of inertia then the tension/force method would work right?
 
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