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## Homework Statement

A small block is oscillating on a spring with a period of 3.05 s. At t = 0 the mass has zero speed and is at x = 4.35 cm. What is the magnitude of the acceleration at t = 4.30 s?

## Homework Equations

a=-Aω

^{2}cos(ωt)

ω=2∏/T

## The Attempt at a Solution

ω=2∏/3.05=2.06

x(0)=Acos(0)=4.35=A(1)=A

so:a=(t)=-4.35(2.06)

^{2}cos(2.60(4.30))=-18.3 m/s

^{2}

which I've been told is wrong.

I have no idea what I'm doing wrong, I'm sure it's something painfully obvious but I just can't figure it out.