Acceleration of Velocity Graph: Finding the Relationship | Worsley School

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Homework Help Overview

The discussion revolves around interpreting a velocity graph and determining the nature of acceleration based on its characteristics. Participants are examining whether the acceleration is zero throughout the entire graph.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between velocity and acceleration, questioning whether constant velocity implies zero acceleration. There is a focus on the instantaneous changes in velocity at specific points in time.

Discussion Status

Some participants have confirmed the notion that the acceleration is zero, suggesting that the acceleration graph would be a straight line on the time-axis. However, there is ongoing clarification regarding the implications of instantaneous changes in velocity.

Contextual Notes

The original poster references specific points in time where velocity changes, indicating a need to consider the nature of these changes in relation to acceleration.

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Homework Statement




http://www.worsleyschool.net/science/files/average/graph1b.gif


Is the acceleration zero for this entire velocity graph?


Homework Equations



v = delta x/ delta t
a= delta v/ delta t

The Attempt at a Solution



If i were to convert this velocity graph to an acceleration graph, i think it would be a straight line on the t-axis.
 
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yes, the velocity is constant all the time, it just changes instantaneously at t=3 and at t=6. If there were non-zero acceleration the velocity would change over time and you would see a slope (upwards or downwards) in a velocity versus time graph.
 
gerben said:
yes, the velocity is constant all the time, it just changes instantaneously at t=3 and at t=6. If there were non-zero acceleration the velocity would change over time and you would see a slope (upwards or downwards) in a velocity versus time graph.

thank you very much for the reply,

but just to make sure: so the acceleration graph of this velocity graph would be just a straight line on the t-axis ( 0 acceleration) ?
 
yes that's correct
 

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