Acceleration-velocity-position graph~

  • Thread starter Thread starter P-Illiterate
  • Start date Start date
  • Tags Tags
    Graph
AI Thread Summary
To draw a velocity vs. time graph from an acceleration vs. time graph, calculate the area under the acceleration curve for the desired time interval, which represents the change in velocity. For a position vs. time graph, take the area under the velocity curve, which indicates the change in position over time. The area from t=0 to t=t1 on the acceleration graph provides the velocity at t=t1. Understanding these relationships is crucial for accurately representing motion in graphs. Mastering these concepts allows for effective visualization of an object's motion.
P-Illiterate
Messages
28
Reaction score
0
How do I draw a velocity vs time graph and a position vs time graph if I'm a given a acceleration vs time graph ?
Thank you :D
 
Physics news on Phys.org
P-Illiterate said:
How do I draw a velocity vs time graph and a position vs time graph if I'm a given a acceleration vs time graph ?
Thank you :D

The area under the acceleration vs. time graph gives the velocity at that point. Similarly, the area under the velocity vs. time graph gives the position.
 
rock.freak667 said:
The area under the acceleration vs. time graph gives the velocity at that point. Similarly, the area under the velocity vs. time graph gives the position.

but I still don't get how I draw it in the graph
 
can someone help mee??!
 
P-Illiterate said:
but I still don't get how I draw it in the graph

For example, the area from t=0 to t=t1, will give the velocity at t= t1.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top