Acceleration where velocity is changing

AI Thread Summary
In circular motion with constant velocity, the acceleration is referred to as centripetal acceleration, which acts towards the center of the circle. Since the velocity remains constant in magnitude, there is no linear (tangential) acceleration or angular acceleration present. The discussion confirms that both angular and tangential accelerations equal zero when peripheral velocity is constant. This understanding is crucial for analyzing motion in a circular path. Overall, the key takeaway is that constant velocity in circular motion results in centripetal acceleration only.
tandoorichicken
Messages
245
Reaction score
0
How would one describe the acceleration (linear and angular) if the velocity is constant but direction is constantly changing, i.e., circular motion?
 
Physics news on Phys.org
If the velocity (circumferential speed) is constant and motion is in a circle, then the acceleration is called centripetal acceleration.
Since the velocity is constant, then there is no linear (i.e. tangential) acceleration, or angular acceleration.

Is that what you were asking about?
 
Thanks fermat, so this means that both angular acceleration and the tangential acceleration = 0?
 
If the peripheral velocity is constant,then that's right, yes.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top